我有这个实体。
@Entity
@Table(name = "CarePlan")
public class CarePlan extends Updateable{
@Column(name = "careplan_system")
private String system;
@Column(name = "careplan_code",unique = true)
private String code;
@Column(name ="description")
private String description;
@OneToMany(fetch = FetchType.EAGER,mappedBy = "carePlan")
private Set<CarePlan> subsections = new HashSet<>();
@ManyToOne(cascade={CascadeType.ALL})
@JoinColumn(name="carePlan_code")
private CarePlan carePlan;
public String getSystem() {
return system;
}
public void setSystem(String system) {
this.system = system;
}
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
public Set<CarePlan> getSubsections() {
return subsections;
}
public void setSubsections(Set<CarePlan> subsections) {
this.subsections = subsections;
}
public CarePlan getCarePlan() {
return carePlan;
}
public void setCarePlan(CarePlan carePlan) {
this.carePlan = carePlan;
}
}
但是，我一直收到此错误
nested exception is org.hibernate.DuplicateMappingException: Table [care_plan] contains logical column name [carePlan_code] referring to multiple physical column names: [careplan_code], [care_plan_code]
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1589)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:554)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:483)
at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:306)
at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:230)
at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:302)
at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:197)
at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:1081)
at org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:856)
at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:542)
at org.springframework.boot.context.embedded.EmbeddedWebApplicationContext.refresh(EmbeddedWebApplicationContext.java:122)
at org.springframework.boot.SpringApplication.refresh(SpringApplication.java:761)
at org.springframework.boot.SpringApplication.refreshContext(SpringApplication.java:371)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:315)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1186)
at org.springframework.boot.SpringApplication.run(SpringApplication.java:1175)
at com.siva.homehealth.SivaHomeHealthApplication.main(SivaHomeHealthApplication.java:47)
Caused by: org.hibernate.DuplicateMappingException: Table [care_plan] contains logical column name [carePlan_code] referring to multiple physical column names: [careplan_code], [care_plan_code]
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl$TableColumnNameBinding.bindLogicalToPhysical(InFlightMetadataCollectorImpl.java:902)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl$TableColumnNameBinding.addBinding(InFlightMetadataCollectorImpl.java:890)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.addColumnNameBinding(InFlightMetadataCollectorImpl.java:961)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.addColumnNameBinding(InFlightMetadataCollectorImpl.java:942)
at org.hibernate.cfg.Ejb3JoinColumn.addColumnBinding(Ejb3JoinColumn.java:788)
at org.hibernate.cfg.Ejb3Column.linkWithValue(Ejb3Column.java:369)
at org.hibernate.cfg.annotations.TableBinder.linkJoinColumnWithValueOverridingNameIfImplicit(TableBinder.java:730)
at org.hibernate.cfg.annotations.TableBinder.bindFk(TableBinder.java:660)
at org.hibernate.cfg.ToOneFkSecondPass.doSecondPass(ToOneFkSecondPass.java:101)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processEndOfQueue(InFlightMetadataCollectorImpl.java:1786)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processFkSecondPassesInOrder(InFlightMetadataCollectorImpl.java:1730)
at org.hibernate.boot.internal.InFlightMetadataCollectorImpl.processSecondPasses(InFlightMetadataCollectorImpl.java:1617)
at org.hibernate.boot.model.process.spi.MetadataBuildingProcess.complete(MetadataBuildingProcess.java:278)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.metadata(EntityManagerFactoryBuilderImpl.java:847)
at org.hibernate.jpa.boot.internal.EntityManagerFactoryBuilderImpl.build(EntityManagerFactoryBuilderImpl.java:874)
at org.springframework.orm.jpa.vendor.SpringHibernateJpaPersistenceProvider.createContainerEntityManagerFactory(SpringHibernateJpaPersistenceProvider.java:60)
at org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean.createNativeEntityManagerFactory(LocalContainerEntityManagerFactoryBean.java:353)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.buildNativeEntityManagerFactory(AbstractEntityManagerFactoryBean.java:373)
at org.springframework.orm.jpa.AbstractEntityManagerFactoryBean.afterPropertiesSet(AbstractEntityManagerFactoryBean.java:362)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.invokeInitMethods(AbstractAutowireCapableBeanFactory.java:1648)
at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1585)
这是我用来生成表格的SQL脚本。
CREATE TABLE CarePlan (
id bigserial NOT null PRIMARY KEY,
time_created timestamptz DEFAULT now() NOT NULL,
time_updated timestamptz DEFAULT now() NOT NULL,
careplan_system VARCHAR(50),
careplan_code VARCHAR(50) UNIQUE,
description VARCHAR(500),
parent_careplan_code VARCHAR(50),
FOREIGN KEY (parent_careplan_code) REFERENCES CarePlan (careplan_code)
);
我错过了什么？
答案 0 :(得分：0)
将您的实体重命名为此类。
@Entity
@Table(schema = "siva", name = "CarePlan")
public class CarePlan extends Updateable {
@Column(name = "careplan_system")
private String system;
@Column(name = "code")
private String code;
@Column(name = "description")
private String description;
@ManyToOne(cascade = {CascadeType.ALL})
@JoinColumn(name = "parent_careplan_code",referencedColumnName = "code")
private CarePlan manager;
@OneToMany(mappedBy = "manager",fetch = FetchType.EAGER)
private Set<CarePlan> subsections = new HashSet<>();
public String getSystem() {
return system;
}
public void setSystem(String system) {
this.system = system;
}
public String getCode() {
return code;
}
public void setCode(String code) {
this.code = code;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
public Set<CarePlan> getSubsections() {
return subsections;
}
public void setSubsections(Set<CarePlan> subsections) {
this.subsections = subsections;
}
public void setManager(CarePlan manager) {
this.manager = manager;
}
public CarePlan getManager() {
return manager;
}
}
注意这个
@JoinColumn(name = "parent_careplan_code",referencedColumnName = "code")
parent_careplan_code是你的外国人的名字
答案 1 :(得分：0)
我发现此问题与spring-boot/2129和HIBERNATE-160有关，该问题的解决方法是添加以下内容：
spring.jpa.hibernate.naming:
implicit-strategy: "org.hibernate.boot.model.naming.ImplicitNamingStrategyLegacyJpaImpl"
physical-strategy: "org.hibernate.boot.model.naming.PhysicalNamingStrategyStandardImpl"
或使用等效的属性文件。