可以从变量中的字符串中评估模板吗?我需要将字符串放在组件而不是表达式中, 例如
template: "<div>{{ template_string }}</div>"
template_string 包含:<b>{{ name }}</b>
并且所有内容都应评估为<div><b>My Name</b></div>
但我看到<div>{{ template_string }}</div>
我需要{{ template_string | eval }}
之类的内容来评估当前上下文中变量的内容。
有可能吗?我需要使用这种方法,因为在使用组件时可以更改template_string
。
Edit1:
Angular Version:4.0.3
E.g。
@Component({
selector: 'product-item',
template: `
<div class="product">{{ template }}</div>`,
})
export class ProductItemComponent {
@Input() name: string;
@Input() price: number = 0;
@Input() template: string = `{{ name }} <b>{{ price | currency }}</b>`;
}
用法:
<product-item [name]="product.name" [price]="product.price"></product-item>
预期:产品名称 USD3.00
输出: {{ name }} <b>{{ price | currency }}</b>
答案 0 :(得分:16)
您可以创建自己的指令来执行此操作:
<强> compile.directive.ts 强>
@Directive({
selector: '[compile]'
})
export class CompileDirective implements OnChanges {
@Input() compile: string;
@Input() compileContext: any;
compRef: ComponentRef<any>;
constructor(private vcRef: ViewContainerRef, private compiler: Compiler) {}
ngOnChanges() {
if(!this.compile) {
if(this.compRef) {
this.updateProperties();
return;
}
throw Error('You forgot to provide template');
}
this.vcRef.clear();
this.compRef = null;
const component = this.createDynamicComponent(this.compile);
const module = this.createDynamicModule(component);
this.compiler.compileModuleAndAllComponentsAsync(module)
.then((moduleWithFactories: ModuleWithComponentFactories<any>) => {
let compFactory = moduleWithFactories.componentFactories.find(x => x.componentType === component);
this.compRef = this.vcRef.createComponent(compFactory);
this.updateProperties();
})
.catch(error => {
console.log(error);
});
}
updateProperties() {
for(var prop in this.compileContext) {
this.compRef.instance[prop] = this.compileContext[prop];
}
}
private createDynamicComponent (template:string) {
@Component({
selector: 'custom-dynamic-component',
template: template,
})
class CustomDynamicComponent {}
return CustomDynamicComponent;
}
private createDynamicModule (component: Type<any>) {
@NgModule({
// You might need other modules, providers, etc...
// Note that whatever components you want to be able
// to render dynamically must be known to this module
imports: [CommonModule],
declarations: [component]
})
class DynamicModule {}
return DynamicModule;
}
}
用法:
@Component({
selector: 'product-item',
template: `
<div class="product">
<ng-container *compile="template; context: this"></ng-container>
</div>
`,
})
export class ProductItemComponent {
@Input() name: string;
@Input() price: number = 0;
@Input() template: string = `{{ name }} <b>{{ price | currency }}</b>`;
}
<强> Plunker Example 强>
另见
答案 1 :(得分:0)
不确定如何构建模板字符串
import { ..., OnInit } from '@angular/core';
@Component({
selector: 'product-item',
template: `
<div class="product" [innerHtml]='template_string'>
</div>`,
})
export class ProductItemComponent implements OnInit {
@Input() name: string;
@Input() price: number = 0;
@Input() pre: string;
@Input() mid: string;
@Input() post: string;
template_string;
ngOnInit() {
// this is probably what you want
this.template_string = `${this.pre}${this.name}${this.mid}${this.price}${this.post}`
}
}
<product-item [name]="name" [price]="price" pre="<em>" mid="</em><b>" post="</b>"></product-item>
字符串可以从组件外部构建,但仍然建议像ngIf这样控制动态模板。
答案 2 :(得分:0)
在Angular双花括号中{{}}
用于评估组件模板中的表达式。而不是处理随机字符串或动态添加DOM元素。所以这样做的一种方法是使用${}
使用typescript字符串插值。检查其余代码以了解
@Component({
selector: 'product-item',
template: `
<div class="product" [innerHTML]="template"></div>`,
})
export class ProductItemComponent {
@Input() name: string;
@Input() price: number = 0;
@Input() template: string = `${ this.name } <b>${ this.price }}</b>`;
}