Question

我想要实现的是让当前登录用户使用关联名称的发件人名称显示在接收者收件箱中，如下所示：

'associaton-name'@domain.com

我在下面评论了它，我试图在views.py

中实现它

在工作了几天和几小时之后似乎无法找到任何相关的解决方案。

真的很感谢你的帮助，伙计们！

Django：1.10
Python：3.6

views.py

class mailPost(FormView):
   success_url = '.'
   form_class = mailHandler
   template_name = 'post/post.html'

   def form_valid(self, form):
       messages.add_message(self.request, messages.SUCCESS, 'Email Sent!')
       return super(mailPost, self).form_valid(form)

   def form_invalid(self, form):
       messages.add_message(self.request, messages.WARNING,
                         'Email not sent. Please try again.')
       return super(mailPost, self).form_invalid(form)

   def post(self, request, *args, **kwargs):
       form_class = self.get_form_class()
       form = self.get_form(form_class)

       if form.is_valid():
           sender = "noreply@domain.com"      # Instead of noreply I wish for current requested associaton name
           receiver = form.cleaned_data.get('receiver')
           cc = form.cleaned_data.get('cc')
           bcc = form.cleaned_data.get('bcc')
           subject = form.cleaned_data.get('subject')
           message = form.cleaned_data.get('message')
           time = datetime.now()
           asoc_pk = Association.objects.filter(asoc_name=self.request.user.association)
           asoc = Association.objects.get(id=asoc_pk)

           Email.objects.create(
               sender=sender,
               receiver=receiver,
               cc=cc,
               bcc=bcc,
               subject=subject,
               message=message,
               association=asoc,
               sentTime=time
           )

           msg = EmailMultiAlternatives(subject, message, sender, [receiver], bcc=[bcc], cc=[cc])
           msg.send()

           return self.form_valid(form)
       else:
           return self.form_invalid(form)

models.py

class Email(models.Model):
   sender = models.CharField(max_length=254)
   sentTime = models.DateTimeField(auto_now_add=True, blank=False)
   subject = models.CharField(max_length=254)
   receiver = models.CharField(max_length=254)
   cc = models.CharField(max_length=254)
   bcc = models.CharField(max_length=254)
   message = models.TextField()
   association = models.ForeignKey(Association)

   class Meta:
       db_table = 'Email'    


class Association(models.Model):
    asoc_name = models.CharField(max_length=50, null=True, blank=True, unique=True)


   class Meta:
       db_table = 'Association'     


class Administrator(AbstractUser):
   ...
   association = models.ForeignKey(Association)


   class Meta:
       db_table = 'Administrator'

Answer 1

我不确定我是否理解你的问题。您可以通过调用self.request.user来访问经过身份验证的用户（假设您使用的是Django身份验证系统）。

您必须在Association与用户之间建立关系：

class Association(models.Model):
    asoc_name = models.CharField(max_length=50, null=True, blank=True, unique=True)
    # Option 1 - if one user can be a member of several associations
    members = models.ManyToMany(User)

   class Meta:
       db_table = 'Association'

或新模型实例，如果用户只能是一个关联的成员：

# Option 2
class Membership(Model):
    association = models.ForeignKey(Association)
    user = models.ForeignKey(User, unique=True)

您使用直接查找（或反向关系）获得关联。

 # option 1
 if form.is_valid():
       sender = Association.objects.filter(members=self.request.user).first()
       # sender might be None

 # option 2
 if form.is_valid():
       membership = Membership.objects.filter(user=self.request.user).first()
       if membership:
           sender = membership.association

https://docs.djangoproject.com/en/1.11/topics/db/examples/many_to_many/

Django - 如何在电子邮件中添加发件人姓名？

1 个答案: