我试图与增量和减量按钮同步进行价格计数器,但是当我点击其中一个按钮(+/-)这不起作用时价格没有变化,我怎么能解决这个问题?感谢!!!
$('#plus').click(function add() {
var $qtde = $("#quantity");
var a = $qtde.val();
a++;
$("#minus").attr("disabled", !a);
$qtde.val(a);
});
$("#minus").attr("disabled", !$("#quantity").val());
$('#minus').click(function minust() {
var $qtde = $("#quantity");
var b = $qtde.val();
if (b >= 1) {
b--;
$qtde.val(b);
}
else {
$("#minus").attr("disabled", true);
}
});
/* On change */
$(document).ready(function()
{
function updatePrice()
{
var price = parseFloat($("#quantity").val());
var total = (price + 1) * 1.05;
var total = total.toFixed(2);
$("#total-price").val(total);
}
$(document).on("change, keyup, focus", "#quantity", updatePrice);
});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="button" value="-" id="minus" />
<input type="text" id="quantity" value="" name="quantity" />
<input type="button" value="+" id="plus" />
<br />
<input id="total-price" readonly="readonly" value=""/>
&#13;
答案 0 :(得分:2)
如果您在输入时单击更改绑定以进行更新,您将获得您期望的行为。
$('#plus').click(function add() {
var $qtde = $("#quantity");
var a = $qtde.val();
a++;
$("#minus").attr("disabled", !a);
$qtde.val(a);
});
$("#minus").attr("disabled", !$("#quantity").val());
$('#minus').click(function minust() {
var $qtde = $("#quantity");
var b = $qtde.val();
if (b >= 1) {
b--;
$qtde.val(b);
} else {
$("#minus").attr("disabled", true);
}
});
/* On change */
$(document).ready(function() {
function updatePrice() {
var price = parseFloat($("#quantity").val());
var total = (price + 1) * 1.05;
var total = total.toFixed(2);
$("#total-price").val(total);
}
// On the click of an input, update the price
$(document).on("click", "input", updatePrice);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="button" value="-" id="minus" />
<input type="text" id="quantity" value="" name="quantity" />
<input type="button" value="+" id="plus" />
<br />
<input id="total-price" readonly="readonly" value="" />