Question

我对SQL很新，我一直在进度数据库上使用SQL，我在下面有以下代码：

Select pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col", Sum(pub."GL_Table"."Amount_Col"), ROUND((pub."GL_Table"."AccMnth_Col")/100,0) AS "Year", MOD(pub."GL_Table"."AccMnth_Col",100) As "Month"
FROM pub."GL_Table"
GROUP BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"
ORDER BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"

我只希望仅显示"Year" 2017

的行

我尝试过以下（但收到错误）：

Select * FROM (
Select pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col", Sum(pub."GL_Table"."Amount_Col"), ROUND((pub."GL_Table"."AccMnth_Col")/100,0) AS "Year", MOD(pub."GL_Table"."AccMnth_Col",100) As "Month"
FROM pub."GL_Table"
GROUP BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"
ORDER BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"
)
WHERE "Year" = 2017

任何人都可以帮助我吗？

提前致谢

Answer 1

虽然子查询是一种方法，但您也可以在where子句中引用计算。

Select pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col", Sum(pub."GL_Table"."Amount_Col"), ROUND((pub."GL_Table"."AccMnth_Col")/100,0) AS "Year", MOD(pub."GL_Table"."AccMnth_Col",100) As "Month"
FROM pub."GL_Table"
WHERE ROUND((pub."GL_Table"."AccMnth_Col")/100,0) = 2017
GROUP BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"
ORDER BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"

Answer 2

您缺少子查询别名。 order by子句应该在子查询之外应用。

group-timeout

Answer 3

我猜你需要列别名和表别名。我对进步并不熟悉，但以下似乎更正确：

SELECT *
FROM (SELECT pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col",
             Sum(pub."GL_Table"."Amount_Col") as "Amount", 
             ROUND((pub."GL_Table"."AccMnth_Col")/100, 0) AS "Year", 
             MOD(pub."GL_Table"."AccMnth_Col", 100) As "Month"
      FROM pub."GL_Table"
      GROUP BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"
      ORDER BY pub."GL_Table"."AccNum_Col", pub."GL_Table"."AccMnth_Col"
     ) ym
WHERE "Year" = 2017

SQL（进行中数据库） - 如何在计算字段上使用Where子句

3 个答案: