Question

我写了以下代码：

<?php
    $listO = $_POST["letter"];

    //print_r($listO);
    //Array ( [0] => A [1] => B [2] => C)

    function to_pg_array($set) {
    settype($set, 'array'); // can be called with a scalar or array
    $result = array();
    foreach ($set as $t) {
        if (is_array($t)) {
            $result[] = to_pg_array($t);
        } else {
            $t = str_replace('"', '\\"', $t); // escape double quote
            if (! is_numeric($t)) // quote only non-numeric values
                $t = '"' . $t . '"';
            $result[] = $t;
        }
    }
    return '{' . implode(",", $result) . '}'; // format

    }

    $pg_array_listO = to_pg_array($listO);

    //print_r($pg_array_list_organisms);
    //{"A","B","C"}

    $conn = pg_connect("host=X dbname=Y user=Z");

    $result = pg_query_params($conn, 'SELECT count(cp.id)
    FROM cp, act, a, t
    WHERE t.tid = a.tid AND
    a.aid = act.aid AND
    act.m = cp.m AND
    t.n = $1 AND
    act.st = $2 AND
    t.o LIKE ANY(ARRAY[$3])', array($t1, $a2, $pg_array_listO));

    while($row = pg_fetch_row($result)) {echo $row[0];}

?>

但是我无法弄清楚如何将数组$pg_array_listO传递给postgres查询。函数to_pg_array将php数组转换为postgres数组，但仍无效。我怎么能这样做？

Answer 1

postgres数组看起来像'{list}'：

t=# select array['a','b','c'];
  array
---------
 {a,b,c}
(1 row)

所以你需要摆脱双引号，否则postgres会将文字理解为身份。

例如$pg_array_listO = str_replace('"', '\\"',to_pg_array($listO))或smth更聪明 - 抱歉 - 我不擅长php

另外修改ANY(ARRAY[$3])至ANY('$3'::text[])，费用array[]或'{}'::text[]将被接受

<强>更新基于

 //print_r($pg_array_list_organisms);
    //{"A","B","C"}

我希望这可行：

$result = pg_query_params($conn, "SELECT count(cp.id)
FROM cp, act, a, t
WHERE t.tid = a.tid AND
a.aid = act.aid AND
act.m = cp.m AND
t.n = $1 AND
act.st = $2 AND
t.o LIKE ANY($3)", array($t1, $a2, str_replace('"', '',to_pg_array($listO))));

介意我更改了引号和SQL以及$ {3}变量的str_replace

这种方法的一个实例：

t=# select 'a' like any('{a,b,c}'::text[]);
 ?column?
----------
 t
(1 row)

如何将php数组传递给任何条件的postgres查询

1 个答案: