Question

考虑实体框架模型：

public class Location
{
    public bool IsCustomer { get; set; }

    public bool IsSupplier { get; set; }
}

public class Customer : Location {}

public class Supplier : Location {}

在这种情况下，我希望将Customer作为别名。每当我收到DbSet<Customer>时，它都会返回Location的所有IsCustomer == true。

这可能吗？谢谢！

Answer 1

签出以下代码以使用指令而不是使用类名本身：

shared_data xcc_z::gzip(data_ref s)
{
  z_stream stream;
  stream.zalloc = NULL;
  stream.zfree = NULL;
  stream.opaque = NULL;
  if (deflateInit2(&stream, Z_DEFAULT_COMPRESSION, Z_DEFLATED, 16 + MAX_WBITS, MAX_MEM_LEVEL, Z_DEFAULT_STRATEGY))
  {
    assert(false);
    return {};
  }
  shared_data d(deflateBound(&stream, s.size()) + 8);
  stream.next_in = const_cast<unsigned char*>(s.data());
  stream.avail_in = s.size();
  stream.next_out = d.data();
  stream.avail_out = d.size() - 8;
  deflate(&stream, Z_FINISH);
  deflateEnd(&stream);
  unsigned char* w = stream.next_out;
    w = write_int_le(4, w, crc32(crc32(0, NULL, 0), s.data(), s.size()));
    w = write_int_le(4, w, s.size());
    return d.substr(0, w - d.data());
}

实体框架类型的别名？

1 个答案: