Question

{
    "John Doe": {
        "Age": 18,
        "Gender": "M"
    },
    "Jane Doe": {
        "Age": 16,
        "Gender": "F"
    },
    "Steve Appleseed":{
        "Age": 21,
        "Gender": "M"
    }
}

使用JavaScript，我如何获得数组

var names = ["John Doe", "Jane Doe", "Steve Appleseed"];

如果它有用，我使用Firebase和JavaScript和jQuery PWA，我需要一个嵌套特定级别的所有对象名称的列表。

Answer 1

首先请注意，这与JSON无关。你拥有的是一个物体。因此，Object.keys将满足您的要求：

var obj = {
  "John Doe": {
    "Age": 18,
    "Gender": "M"
  },
  "Jane Doe": {
    "Age": 16,
    "Gender": "F"
  },
  "Steve Appleseed": {
    "Age": 21,
    "Gender": "M"
  }
}

var keys = Object.keys(obj);
console.log(keys);

console.log(obj[keys[0]]["Age"]); // John Doe's age

Answer 2

您可以使用Object.keys(obj)

有关详细信息，请参阅here

＆＃13;

var obj = {
    "John Doe": {
        "Age": 18,
        "Gender": "M"
    },
    "Jane Doe": {
        "Age": 16,
        "Gender": "F"
    },
    "Steve Appleseed":{
        "Age": 21,
        "Gender": "M"
    }
};

var result = Object.keys(obj);

console.log(result);

＆＃13;

Answer 3

试试这个

var obj = {
    "John Doe": {
        "Age": 18,
        "Gender": "M"
    },
    "Jane Doe": {
        "Age": 16,
        "Gender": "F"
    },
    "Steve Appleseed":{
        "Age": 21,
        "Gender": "M"
    }
}

    console.log(Object.keys(obj))

Answer 4

您可以使用object.keys(); 有关详细信息，请查看https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/keys

t = {
    "John Doe": {
        "Age": 18,
        "Gender": "M"
    },
    "Jane Doe": {
        "Age": 16,
        "Gender": "F"
    },
    "Steve Appleseed":{
        "Age": 21,
        "Gender": "M"
    }
}

Object.keys(t);

获取每个嵌套级别的对象列表

4 个答案: