Question

以下是代码：

    import os
    from tkinter.filedialog import askopenfilename
    from tkinter import *

#~~~~ FUNCTIONS~~~~

    def open_file_1():
        global file_path_1

        filename_1 = askopenfilename()
        file_path_1 = os.path.dirname(filename_1) + filename_1
        entry_1.delete(0, END)
        entry_1.insert(0, file_path_1)
        return file_path_1

    def open_file_2():
        global file_path_2

        filename_2 = askopenfilename()
        file_path_2 = os.path.dirname(filename_2) + filename_2
        entry_3.delete(0, END)
        entry_3.insert(0, file_path_2)
        return file_path_2

        def title_name_1():
            global title_1
            title_1=str(entry_4.get())
            return title_1

        def title_name_2():
            global title_2
            title_2=str(entry_5.get())
            return title_2

    def process_file(content):
        print(file_path_1)
        print(file_path_2)
        print(title_1)
        print(title_2)

  #~~~~~~ GUI ~~~~~~~~

root = Tk()
root.title('Test Project')
root.geometry("698x220+350+200")

mf = Frame(root)
mf.pack()


f1 = Frame(mf, width=600, height=250)
f1.pack(fill=X)
f3 = Frame(mf, width=600, height=250)
f3.pack(fill=X)
f4 = Frame(mf, width=600, height=250)
f4.pack(fill=X)
f5 = Frame(mf, width=600, height=250)
f5.pack(fill=X)

f2 = Frame(mf, width=600, height=250)
f2.pack()



file_path_1 = StringVar
file_path_2 = StringVar
title_1 = StringVar
title_2 = StringVar


Label(f1,text="Select File 1").grid(row=0, column=0, sticky='e')
Label(f3,text="Select File 2").grid(row=0, column=0, sticky='e')
Label(f4,text="Title1").grid(row=0, column=0, sticky='e')
Label(f5,text="Title2").grid(row=0, column=0, sticky='e')

entry_1 = Entry(f1, width=50, textvariable=file_path_1)
entry_1.grid(row=0,column=1,padx=2,pady=2,sticky='we',columnspan=25)
Button(f1, text="Browse", command=open_file_1).grid(row=0, column=27, sticky='ew', padx=8, pady=4)


entry_3 = Entry(f3, width=50, textvariable=file_path_2)
entry_3.grid(row=0,column=1,padx=2,pady=2,sticky='we',columnspan=25)
Button(f3, text="Browse", command=open_file_2).grid(row=0, column=27, sticky='ew', padx=8, pady=4)

entry_4 = Entry(f4, width=50,textvariable=title_1)
entry_4.grid(row=0,column=1,padx=5,pady=2,sticky='we',columnspan=25)

entry_5 = Entry(f5, width=50,textvariable=title_2)
entry_5.grid(row=0,column=1,padx=5,pady=2,sticky='we',columnspan=25)

Button(f2, text="Submit", width=32, command=lambda: process_file(content)).grid(sticky='ew', padx=10, pady=70)

root.mainloop()

我想获取这4个字段（file_path_1，file_path_2，Title1，Title2）并存储它们以便可以用于进一步操作。我正在使用浏览以选择文件，用户将输入Title1和Title2的文本。我是新手，所以没有太多想法。

Answer 1

使用StringVar()，您不必要地使您的生活变得复杂。如果你将observer callbacks附加到它们上，StringVar最有用......

大部分时间用于Entry小部件，最好在使用之前使用.get()方法获取内容：

def process_file():
    # Get Entry box content
    filename_1 = entry_1.get()
    # Do something with it
    print(filename_1)

使用tkinter中的entry.get（）获取文本并存储到变量

1 个答案: