我正在尝试创建一个包含3个缩略图的行,问题是它没有在一行中对齐,而是每个缩略图都在不同的行中。
echo "<table>";
echo "<tr>";
echo "</tr>";
while($row=mysqli_fetch_array($result)){
echo "<div class=\"container\">";
echo "<div class=\"row-fluid\">";
echo "<div class=\"col-md-4\">";
echo "<div class=\"thumbnail\">";
echo "<img alt=\"News\" src=\"images/{$row["image"]}\">";
echo "<div class=\"caption\">";
echo "<h3>{$row["title"]}</h3>";
echo "<p>{$row["caption"]}</p>";
echo "<p align=\"right\">";
echo "<a class=\"btn btn-primary\" href=\"{$row["newsupdate"]}\">Read More</a>";
echo "</p>";
echo "</div>";
echo "</div>";
echo "</div>";
echo "</div>";
echo "</div>";
答案 0 :(得分:0)
试试这可能有效
echo "<table>";
echo "<tr>";
while($row=mysqli_fetch_array($result)){
echo "<img alt=\"News\" src=\"images/{$row["image"]}\">";
echo "<div class=\"caption\">";
echo " <td> <h3>{$row["title"]}</h3> </td> ";
echo "<td><p>{$row["caption"]}</p></td>";
echo "<td> <a class=\"btn btn-primary\" href=\{$row["newsupdate"]}\">Read More</a>";
echo "</td>";
}
echo "</tr>";
echo "</table>";