这是我的代码我正在调用成员函数prepare（）on null我的代码错误可以任何人请帮我解决这个问题。这个问题在它正常工作前几天突然发生，但现在它在我尝试将用户名和密码添加到文本字段时显示
class LoginSystem {
/* Start Config */
private $dbhost = "";
private $dbport = "";
private $dbuser = "";
private $dbpass = "";
private $dbname = "";
private $dbtable = "";
private $pages = "";
private $news = "";
private $doct = "";
private $health = "";
private $dept = "";
private $features = "";
private $epages = "";
private $tips = "";
private $core = "";
private $banner = "";
private $secureKey = "";
private $passwordSalt = "";
private $company = "xyz";
var $phpsessionstart = true;
var $emailLogin = false;
var $rememberMe = false;
public $staticPages = array(
"/register.php"
);
private $loginPage = "/index.php";
private $homePage = "/home.php";
public $loggedIn = false;
public $db = true;
public $user = false;
private $cookie;
private $session;
private $remCook;
private $dbh;
private $initCalled = false;
public function __construct(){
if($this->phpsessionstart == true){
session_start();
}
try{
array_push($this->staticPages, $this->loginPage);
$this->dbh = new PDO("mysql:dbname={$this->dbname};host={$this->dbhost};port={$this->dbport}", $this->dbuser, $this->dbpass,array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"
));
$this->db = true;
$this->cookie = isset($_COOKIE['logSyslogin']) ? $_COOKIE['logSyslogin'] : false;
$this->session = isset($_SESSION['logSyscuruser']) ? $_SESSION['logSyscuruser'] : false;
$this->remCook = isset($_COOKIE['logSysrememberMe']) ? $_COOKIE['logSysrememberMe'] : false;
$encUserID = hash("", "{$this->secureKey}{$this->session}{$this->secureKey}");
$this->loggedIn = $this->cookie == $encUserID ? true : false;
if($this->rememberMe === true && isset($this->remCook) && $this->loggedIn === false){
$encUserID = hash("", "{$this->secureKey}{$this->remCook}{$this->secureKey}");
$this->loggedIn = $this->cookie == $encUserID ? true : false;
if($this->loggedIn === true){
$_SESSION['logSyscuruser'] = $this->remCook;
}
}
$this->user = $this->session;
return true;
}catch( PDOException $e ) {
return false;
}
}
public function init() {
if( $this->loggedIn && array_search($this->curPage(), $this->staticPages) !== false ){
$this->redirect($this->homePage);
}elseif( !$this->loggedIn && array_search($this->curPage(), $this->staticPages) === false ){
$this->redirect($this->loginPage);
}
$this->initCalled = true;
}
public function login($username, $password, $cookies = true){
if($this->db === true){
/* We Add LIMIT to 1 in SQL query because we need to just get an array of data with key as the column name. Nothing else. */
if($this->emailLogin === true){
$query = "SELECT `id`, `password`, `password_salt` FROM `{$this->dbtable}` WHERE `username`=:login OR `email`=:login ORDER BY `id` LIMIT 1";
}else{
$query = "SELECT `id`, `password`, `password_salt` FROM `{$this->dbtable}` WHERE `username`=:login ORDER BY `id` LIMIT 1";
}
$sql = $this->dbh->prepare($query);
$sql->bindValue(":login", $username);
$sql->execute();
if($sql->rowCount()==0){
return false;
}else{
/* Get the user details */
$rows = $sql->fetch(PDO::FETCH_ASSOC);
$us_id = $rows['id'];
$us_pass = $rows['password'];
$us_salt = $rows['password_salt'];
$saltedPass = hash('', "{$password}{$this->passwordSalt}{$us_salt}");
if($saltedPass == $us_pass){
if($cookies === true){
$_SESSION['logSyscuruser'] = $us_id;
setcookie("logSyslogin", hash("", $this->secureKey.$us_id.$this->secureKey), time()+3600*99*500, "/");
if( isset($_POST['remember_me']) && $this->rememberMe === true ){
setcookie("logSysrememberMe", $us_id, time()+3600*99*500, "/");
}
$this->loggedIn = true;
if( $this->initCalled ){
$this->redirect($this->homePage);
}
}
return true;
}else{
return false;
}
}
}
}
答案 0 :(得分：0)
对不起，这不是一个答案，但需要空间来输入所有
删除一些代码并添加debug echos：
<?php
class LoginSystem {
/* Start Config */
private $dbhost = "";
private $dbport = "";
private $dbuser = "";
private $dbpass = "";
private $dbname = "";
private $dbtable = "";
private $dbh;
public $db = true;
public function __construct(){
try{
echo '<p>trying to create connection</p>'; // Debug echo
$this->dbh = new PDO("mysql:dbname={$this->dbname};host={$this->dbhost};port={$this->dbport}", $this->dbuser, $this->dbpass,array(
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION,
PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8"
));
$this->db = true;
echo '<p>made it</p>'; // Debug echo
return true;
}catch( PDOException $e ) {
echo '<p>'.$e->getMessage() . ' - Failing</p>'; // Debug echo
return false;
}
}
public function login($username, $password, $cookies = true){
if($this->db === true){
/* We Add LIMIT to 1 in SQL query because we need to just get an array of data with key as the column name. Nothing else. */
if($this->emailLogin === true){
$query = "SELECT `id`, `password`, `password_salt` FROM `{$this->dbtable}` WHERE `username`=:login OR `email`=:login ORDER BY `id` LIMIT 1";
}else{
$query = "SELECT `id`, `password`, `password_salt` FROM `{$this->dbtable}` WHERE `username`=:login ORDER BY `id` LIMIT 1";
}
echo "<pre>"; // Debug string
var_dump($this->dbh); // Debug string
echo "</pre>"; // Debug string
$sql = $this->dbh->prepare($query);
$sql->bindValue(":login", $username);
$sql->execute();
if($sql->rowCount()==0){
return false;
}else{
return true;
}
}
}
}
$a = new LoginSystem();
$a->login('a','b');
我发现你的代码在给出正确的凭据和表名（我假设你硬编码为私有变量）的情况下有效。此外，你得到的准备警告通常意味着$this->dbh不是正确的对象或未定义，请尝试在我拥有的位置添加var_dump()，并告诉我们$this->dbh的内容。
对于某些事情你可以尝试：
请检查数据库主机上的配置，名称，通行证，端口等
同时检查您的PDO是否已启用，并检查您自己的错误消息以获取更多信息
最后将您的password_salt存储在您的用户数据库中通常不是一个好主意，它与锁定您的房子并将您的钥匙放在门垫下相同。