威化。
编辑:解决方案
正如MartineJ和emilliman5所指出的,节点应该是唯一标记的(下图)。
library("riverplot")
nodes<-structure(list(ID = c("2011+", "2011-", "2016+", "2016-"), x = c(20,
20, 30, 30), y = c(50, 40, 50, 40)), class = "data.frame", row.names = c(NA,
-4L))
edges<-structure(list(N1 = c("2011+", "2011-", "2011+", "2011-"), N2 =
c("2016+", "2016-", "2016-", "2016+"), Value = c(461, 7, 0, 46)), class =
"data.frame", row.names = c(NA, -4L))
river <- makeRiver(nodes,edges)
riverplot(river)
我一直想要绘制一个Sankey图/河图(使用riverplot包)来描述癌症注册随时间的变化,尽管这段代码到目前为止我没那么成功。任何人都可以指导我解释这段代码的错误吗?
Warning message: In checkedges(x2$edges, names(x2)) : duplicated edge information, removing 1 edges
这是可疑代码:
library(“riverplot”)
edges<-structure(list(N1 = c("+", "-", "+", "-"), N2 = c("+", "-", "-", "+"), Value = c(664L, 50L, 0L, 46L)), .Names = c("N1", "N2", "Value"), class = "data.frame", row.names = c(NA, -4L))
nodes = data.frame(ID = unique(c(edges$N1, edges$N2)), stringsAsFactors = FALSE)
nodes$x = c(1,2)
rownames(nodes) = nodes$ID
rp <- list(nodes=nodes, edges=edges)
class(rp) <- c(class(rp), "riverplot")
plot(rp)
数据,包含在代码中:
N1 N2 Value
+ + 664
- - 50
+ - 0
- + 46
永远感激。
答案 0 :(得分:1)
看起来你在N1(和N2)中多次使用相同的值。尝试使它们完全不同(每列),然后再试一次,f.i。:
N1:plus1减1加2减2
如果你想在makeRiver中显示只有+和 - :,有一个选项** node_labels **
答案 1 :(得分:0)
您的节点需要唯一命名,然后使用nodes$labels
将其更改回来:
library(riverplot)
edges<-structure(list(N1 = c("+", "-", "+", "-"), N2 = c("+", "-", "-", "+"), Value = c(664L, 50L, 0L, 46L)), .Names = c("N1", "N2", "Value"), class = "data.frame", row.names = c(NA, -4L))
edges$N1 <- paste0(edges$N1, "a")
edges$N2 <- paste0(edges$N2, "b")
nodes = data.frame(ID = unique(c(edges$N1, edges$N2)), stringsAsFactors = FALSE)
nodes$x = c(1,1,2,2)
nodes$labels <- as.character(substr(nodes$ID, 1, 1))
rownames(nodes) = nodes$ID
rp <- list(nodes=nodes, edges=edges)
class(rp) <- c(class(rp), "riverplot")
plot(rp)