Question

我需要一些帮助，我需要从我的数据库中提取数据，现在我有一个FD_Documents表和FD_Revision表。

我需要匹配两个表中的GUID，并且还需要是大于2的修订版，一旦匹配完成，它必须在结果中添加新列，QC'ed“1”用于匹配条件或者“0”表示不匹配标准。

我写了下面的内容，但它没有给我结果。

select Case when EXISTS (
       SELECT FD_Documents.GUID,
      FD_Documents.FD_C231FD9A as [Store],
      FD_Documents.FD_97CDB35A as [Store 2],
      FD_Documents.FD_8B9BD5C6 as [Transaction Date],
      FD_Documents.FD_84A4EF1A as [Account Number],
      FD_Documents.FD_1A3D602F as [Name],
      FD_Documents.FD_F8EFD019 as [Date of Birth],
      FD_Documents.FD_9DAADEC8 as [Document Type],
      FD_Documents.FD_8B43AE0B as [Year],
      FD_Documents.FD_E77BE253 as [File Name]
      FROM FD_Documents, FD_Revisions
      WHERE FD_Documents.GUID = FD_Revisions.GUID
      AND FD_Documents.Deleted = '0'
      AND FD_Revisions.Revision < '3')
      THEN CAST(1 as bit)
      ELSE CAST(0 AS bit) END

Answer 1

我假设FD_Documents.Deleted是一个int或bit（不是你帖子中的字符串），并且该版本是一个int（并且应该大于2，就像你的问题描述中的代码而不是你的代码），

SELECT FD_Documents.GUID,
  FD_Documents.FD_C231FD9A as [Store],
  FD_Documents.FD_97CDB35A as [Store 2],
  FD_Documents.FD_8B9BD5C6 as [Transaction Date],
  FD_Documents.FD_84A4EF1A as [Account Number],
  FD_Documents.FD_1A3D602F as [Name],
  FD_Documents.FD_F8EFD019 as [Date of Birth],
  FD_Documents.FD_9DAADEC8 as [Document Type],
  FD_Documents.FD_8B43AE0B as [Year],
  FD_Documents.FD_E77BE253 as [File Name],
  CASE ISNULL(FD_Revisions.GUID,'') WHEN '' THEN 0 ELSE 1 END AS IsMatching
  FROM FD_Documents LEFT JOIN FD_Revisions
  ON FD_Documents.GUID = FD_Revisions.GUID
  AND FD_Documents.Deleted = 0
  AND FD_Revisions.Revision > 2

Answer 2

这将为您提供所需状态的不同GUID列表

import _ from 'lodash';

Answer 3

像这样的东西

  SELECT FD_Documents.GUID,
      FD_Documents.FD_C231FD9A as [Store],
      FD_Documents.FD_97CDB35A as [Store 2],
      FD_Documents.FD_8B9BD5C6 as [Transaction Date],
      FD_Documents.FD_84A4EF1A as [Account Number],
      FD_Documents.FD_1A3D602F as [Name],
      FD_Documents.FD_F8EFD019 as [Date of Birth],
      FD_Documents.FD_9DAADEC8 as [Document Type],
      FD_Documents.FD_8B43AE0B as [Year],
      FD_Documents.FD_E77BE253 as [File Name],
  case when r.GUID IS NULL then 1 else 0 end [MatchCount]
  FROM FD_Documents d
        LEFT JOIN  FD_Revisions r on d.GUID = r.GUID AND FD_Revisions.Revision > '2' 
  where FD_Documents.Deleted = '0'

我不能肯定地说，但是这是个主意，如果你提供一些测试数据，这个查询可能更具体，因为这个查询没有经过测试

匹配两个表

3 个答案: