Question

我们有一个log表，其中包含以下列：job name,start time,end time, status,source count, target count,reject count,error count等。

每条记录将包含有关每项工作的信息。我的结果应该是job name,start dt,end dt, status,source count, target count,reject count,error count(Today entry),source count, target count,reject count,error count(yesterday count)

我们需要记录今天和今天的记录数量。我们目前正在使用以下查询获取记录。

select * from logtable where start dt=current_date

任何人都可以帮我用SQL来获得上述结果。

Answer 1

好的，基于您的更新的新anser：

echo my-trigger-name > /sys/class/leds/.../trigger

以上内容适合您。你说这些列被命名为“开始时间”，但在选择中你使用“start dt”？

旧答案：

如果您只想要今天和昨天的两行在同一行上，您可以这样做：

select  logToday.`job name`,
        logToday.`start time`,
        logToday.`end time`, 
        logToday.status,
        logToday.`source count`,
        logToday.`target count`,
        logToday.`reject count`,
        logToday.`error count`,
        logYesterday.`source count`, 
        logYesterday.`target count`,
        logYesterday.`reject count`,
        logYesterday.`error count`
from logtable logToday
join logtable logYesterday on logYesterday.`start time` = subdate(current_date, 1)
where logToday.`start time` = current_date;

如果我错过了什么，请提供更多信息，我会修改答案。

SQL今天获取以及单行中的昨天记录

1 个答案: