python - 检查列表中是否存在确切的值集

Question

我试图找出列表中的值是否存在于另一个列表中。 例如：

list1 = ['a','b']

list2 = ['a','b','c','d','e','a','b','c']

list3 = ['a','a','b','b','b','a','b','a']

我想检查list1和list2中是否存在list 3中的值list2。但是，当我与list2进行比较时，检查应该返回false，因为public func jsonPrint(_ o: NSObject, spacing: String = "", after: String = "", before: String = "") { let newSpacing = spacing + " " if o.isArray() { print(before + "[") if let a = o as? Array<NSObject> { for object in a { jsonPrint(object, spacing: newSpacing, after: object == a.last! ? "" : ",", before: newSpacing) } } print(spacing + "]" + after) } else { if o.isDictionary() { print(before + "{") if let a = o as? Dictionary<NSObject, NSObject> { for (key, val) in a { jsonPrint(val, spacing: newSpacing, after: ",", before: newSpacing + key.description + " = ") } } print(spacing + "}" + after) } else { print(before + o.description + after) } } } 除了＆＃39; a＆＃39;之外还有其他值。 ＆安培; ＆＃39; B＆＃39 ;.与list3相比，检查应该返回true，因为它只有＆＃39; a＆＃39; b＆＃39;。任何线索我怎么能这样做？

希望这很清楚。

Answer 1

使用套装：

>>> set(list1) == set(list2)
False
>>> set(list1) == set(list3)
True

Answer 2

尝试all，

In [11]: all(i in list1 for i in list2)
Out[11]: False

In [12]: all(i in list1 for i in list3)
Out[12]: True