我必须使用Java
网络服务。服务方法的签名是
public bool UpsertEmployee(Employee employe);
问题是,在生成SOAP
时,对于具有null值的属性,请求中不包含相应的XML
元素。结果是:
...
<Employee>
<id>1</id>
<firstName>Jhonny</firstName>
</Employee>
我想成为:
...
<Employee>
<id>1</id>
<firstName>Jhonny</firstName>
<lastName/>
</Employee>
有没有办法实现这个目标?
我可以在mehod调用之前设置属性吗?
var client= new EmployeeServiceClient();;
// Can I do something here to accoplish my goal?
client.UpsertEmployee(new Employee{
id = "1",
firstname = "Jhonny"
});
生成的Employee
类代码是
[System.CodeDom.Compiler.GeneratedCodeAttribute("System.Xml", "4.0.30319.36366")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(Namespace = "urn:mve.go.all.mdg.vendor")]
public partial class Employee : object, System.ComponentModel.INotifyPropertyChanged
{
private string idField;
private string firstNameField;
private string lastNameField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified, Order = 0)]
public string id
{
get
{
return this.idField;
}
set
{
this.idField = value;
this.RaisePropertyChanged("id");
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified, Order = 1)]
public string firstName
{
get
{
return this.firstNameField;
}
set
{
this.firstNameField = value;
this.RaisePropertyChanged("firstName");
}
}
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified, Order = 3)]
public string lastName
{
get
{
return this.lastNameField;
}
set
{
this.lastNameField = value;
this.RaisePropertyChanged("lastName");
}
}
public event System.ComponentModel.PropertyChangedEventHandler PropertyChanged;
protected void RaisePropertyChanged(string propertyName)
{
System.ComponentModel.PropertyChangedEventHandler propertyChanged = this.PropertyChanged;
if ((propertyChanged != null))
{
propertyChanged(this, new System.ComponentModel.PropertyChangedEventArgs(propertyName));
}
}
}
我无法修改文件代码,因为将来可能需要更新服务引用。
答案 0 :(得分:3)
您的课程标有XmlSerializer
attributes,因此您似乎正在使用该序列化程序。
您的问题是lastName
属性为null
。如 Xsi:nil Attribute Binding Support 中所述:
将对象序列化为XML文档时:如果
XmlSerializer
类遇到对应于XML元素的对象的空引用,则它会生成一个指定xsi:nil="true"
的元素或完全保留该元素,取决于nillable="true"
设置是否适用。
因此,默认情况下,当lastName
为null时,不会发出任何元素。如果你要设置[XmlElementAttribute(IsNullable = true)]
,你会得到
<Employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<id>1</id>
<firstName>Jhonny</firstName>
<lastName xsi:nil="true" />
</Employee>
不你想要什么(无论如何你都无法更改自动生成的代码)。
相反,您需要将lastName
初始化为空字符串:
var employee = new Employee
{
id = "1",
firstName = "Jhonny",
lastName = "",
};
然后将生成以下XML:
<Employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<id>1</id>
<firstName>Jhonny</firstName>
<lastName />
</Employee>
或者,由于自动生成的代码没有默认构造函数,您可以在单独的partial class
代码文件中自行添加一个。由于它独立于自动生成的代码文件,因此在重新生成生成的代码时不会被覆盖:
public partial class Employee
{
public Employee()
{
this.firstName = this.lastName = this.id = "";
}
}