通过csv中的标题拆分.CSV然后转换为字符串列表

Question

我正在用Python编写代码（我对Python很陌生）并希望拆分一个类似于下面示例的.csv文件。我希望每个包含csv行的项目列表，然后我知道如何拆分，使用：

values = line.split（＆＃39;，＆＃39;）

弃1

0.058824,0.529032,0.367347,0.23913,0.169471,0.243354,0.115713,0.433333,yes
0.529412,0.812903,0.510204,0.26087,0.169471,0.527607,0.13877,0.366667,yes

弃2

0.176471,0.806452,0.510204,0.130435,0.133413,0.239264,0.081127,0.166667,yes
0.411765,0.632258,0.673469,0.184783,0.560096,0.249489,0.021349,0.366667,yes

弃3

0.647059,0.606452,0.510204,0.206522,0.15625,0.366053,0.204526,0.483333,yes
0.411765,0.8,0.653061,0.380435,0.36899,0.408998,0.302733,0.316667,yes

理想情况下，我们希望：

list[0] = ["0.058824,0.529032,0.367347,0.23913,0.169471,0.243354,0.115713,0.433333,yes" , "0.529412,0.812903,0.510204,0.26087,0.169471,0.527607,0.13877,0.366667,yes"] 
list[1] = ["0.176471,0.806452,0.510204,0.130435,0.133413,0.239264,0.081127,0.166667,yes" , "0.411765,0.632258,0.673469,0.184783,0.560096,0.249489,0.021349,0.366667,yes"]

等等。 非常感谢您提供的任何帮助：）

Answer 1

value = (line.split(' '))[-1].split(",")

首先按空格分割，然后拾取最后一个元素，然后按＆＃34;，＆＃34;试。

Answer 2

list1 = []
with open (filename,'r') as file:
    data = file.read()
    if data != '':
        list1.append(data[7:])

list1将包含您提到的列表