我有成功的ajax调用我有没有显示的bootstrap模型
这是代码
$(document).ready(function() {
$('form').submit(function(e){
var name = $('#name').val();
var email = $('#email').val();
var message = $('#message').val();
var data = 'name=' + name + '&email=' + email + '&message=' + message;
$.ajax({
type: "post",
url: 'script.php',
data: data,
success: $(document)ready(function(){
$("#myModal").modal('show');
)
});
e.preventDefault(); // avoid to execute the actual submit of the form.
});
});
答案 0 :(得分:0)
您的代码中存在一些错误和语法错误
试试这个
$(document).ready(function() {
$('form').submit(function(e){
var name = $('#name').val();
var email = $('#email').val();
var message = $('#message').val();
var data = 'name=' + name + '&email=' + email + '&message=' + message;
$.ajax({
type: "post",
url: 'script.php',
data: data,
success: $(document).ready(function(){ //missing . before ready
$("#myModal").modal("show");
}) // you was missing } here
});
e.preventDefault(); // avoid to execute the actual submit of the form.
});
});