我有if(this.exercisesDoneArray[ind][i].done && this.exercisesDoneArray[ind][1].done
这样:
&& this.exercisesDoneArray[ind][i].exercise === this.slides.clickedSlide.nextElementSibling.nextElementSibling.id
|| this.exercisesDoneArray[ind][1].exercise === this.slides.clickedSlide.nextElementSibling.nextElementSibling.id){
select to_timestamp(20130216131736::text, 'YYYYMMDDHH24MISS')
但我想知道如何缩短这个......
答案 0 :(得分:4)
如何使用一些变量?
var ex1 = this.exercisesDoneArray[ind][i],
ex2 = this.exercisesDoneArray[ind][1],
nextSlide = this.slides.clickedSlide.nextElementSibling.nextElementSibling.id;
if(ex1.done && ex2.done && ex1.exercise === nextSlide || ex2.exercise === nextSlide){
答案 1 :(得分:0)
使用少量变量,然后将其放在全局之外,如果你检查你的主要练习是否已经完成另外一个,因为它总是要完成,因此如果使用和
,则不需要总是在另一个内部检查var currentExcercise = this.exercisesDoneArray[ind][i];
var baseExcercise = this.exercisesDoneArray[ind][1];
var slideId = this.slides.clickedSlide.nextElementSibling.nextElementSibling.id;
if (!baseExcercise.done) {
return false;
}
if(currentExcercise.done && currentExcercise.exercise === slideId || baseExcercise .exercise === slideId ){