Question

在python中是否有办法将两个路径与os.path或任何其他不重复常见子文件夹的库组合在一起？即。

root = '/home/user/test'

rel_path = 'test/files/file.txt'

os.combine(root, rel_path)

返回/home/user/test/files/file.txt代替/home/user/test/test/files/file.txt

Answer 1

我认为你必须手动完成，我不认为os.path实现了这个功能。

也许尝试类似的事情：

def combine_with_duplicate(root, rel_path):
    rs = root.split("/")
    rps = rel_path.split("/")
    popped = False
    for v in rs:
        if v == rps[0]:
            rps.pop(0)
            popped = True
        elif popped:
            break

    return "/".join(rs+rps)


print(combine_with_duplicate('/home/user/test', 'test/files/file.txt'))
# /home/user/test/files/file.txt
print(combine_with_duplicate('/home/user', 'test/files/file.txt'))
# /home/user/test/files/file.txt
print(combine_with_duplicate('/home/user/test', 'user/test/files/file.txt'))
# /home/user/test/files/file.txt

Answer 2

您可以使用os.path.join：

import os

root = '/home/user/test'

rel_path = 'test/files/file.txt'

head, tail = os.path.split(root)
final = os.path.join(head, rel_path)

print(final)
#  /home/user/test/files/file.txt

Answer 3

你可以尝试：

>>> import os
>>> root = '/home/user/test'
>>> rel_path = 'test/files/file.txt'
>>> os.path.join(root, '../', rel_path)
'/home/user/test/../test/files/file.txt'

或者，如果root和rel_path没有重叠＆＃39;部分：

>>> os.path.join(root, '../' if root.split('/')[-1] == rel_path.split('/')[0] else '' , rel_path)
'/home/user/test/../test/files/file.txt'
>>> root =  '/home/user/test/files'
>>> os.path.join(root, '../' if root.split('/')[-1] == rel_path.split('/')[0] else '' , rel_path)
'/home/user/test/files/test/files/file.txt'

将两个路径与公共文件夹

3 个答案: