查询从2个表中获取结果:
SELECT path.* FROM (SELECT tbc.course_name
slp.course_id,slp.student_type,slp.stu_reference_id,
count(slp.course_id) as counttotalWatchedStudents
from tbl_student_learning_path slp LEFT JOIN tbl_courses tbc
on tbc.course_pid = slp.course_id WHERE slp.stu_reference_id =34
and slp.student_type='institute' GROUP BY slp.course_id ) as path
查询结果表:
| course_id | totalCollegeStudents | fullwatchedStudentsCount | counttotalWatchedStudents | sumOfWatchPointsForWatchedStudents | totalStudentsAvg | fullwatchedAvg |
|-------------------------------|----------------------|--------------------------|---------------------------|------------------------------------|------------------|----------------|
| Number Systems | 9 | 0 | 3 | 60 | 20.0000 | 0 |
| Percentages | 9 | 0 | 3 | 30 | 10.0000 | 0 |
| Blood Relations | 9 | 3 | 3 | 300 | 100.0000 | 300 |
| Calandar | 9 | 3 | 3 | 300 | 100.0000 | 300 |
| Percentages | 9 | 3 | 3 | 300 | 100.0000 | 300 |
| Permutation & Combination | 9 | 3 | 3 | 300 | 100.0000 | 300 |
| Probability | 9 | 0 | 3 | 90 | 30.0000 | 0 |
| Ratios | 9 | 0 | 3 | 120 | 40.0000 | 0 |
| Time and Work | 9 | 0 | 3 | 150 | 50.0000 | 0 |
| Time Speed & Distance | 9 | 1 | 3 | 140 | 46.6667 | 100 |
| Averages | 9 | 3 | 3 | 300 | 100.0000 | 300 |
| Coding and Decoding | 9 | 3 | 3 | 300 | 100.0000 | 300 |
从上表中,我想将内部查询添加到主查询中 查询应该是这样的:
( select count(t1.watched_percentage) from tbl_student_learning_path t1
WHERE t1.stu_reference_id =34 and t1.student_type='institute'
AND t1.watched_percentage >= 90 group by t1.course_id )
fullwatchedStudentsCount,
结果应该是这样的(这只是如果第一个表counttotalWatchedStudents值为3则表示有两种类型的人 1.学生们看完了(watched_percentage> = 90) 2.学生们仍在观看(watched_percentage 1-89) )
| fullwatchedStudentsCount | fullwatchedStudentsSum |
|--------------------------|------------------------|
| 2 | 200 |
| 1 | 100 |
| 0 | 0 |
| 2 | 200 |
| 1 | 100 |
| 1 | 100 |
| 0 | 0 |
| 2 | 200 |
| 2 | 200 |
| 1 | 100 |
| 2 | 200 |
| 1 | 100 |
答案 0 :(得分:2)
如果我理解正确,你想要总结那些在另一栏中看到超过90%的学生:
我这样做:
SELECT tbc.course_name,
slp.course_id,
slp.student_type,
slp.stu_reference_id,
count(slp.course_id) AS counttotalWatchedStudents,
sum(if(slp.watched_percentage>=90, 1, 0)) AS fullwatchedStudentsCount
sum(if(slp.watched_percentage>=90, watched_percentage, 0)) AS fullwatchedStudentsSum
FROM tbl_student_learning_path slp
LEFT JOIN tbl_courses tbc ON tbc.course_pid = slp.course_id
WHERE slp.stu_reference_id =34
AND slp.student_type='institute'
GROUP BY slp.course_id
enter code here
希望这有帮助
答案 1 :(得分:2)
所以你想用watched_percentage >= 90
计算学生?使用条件聚合:
SELECT
tbc.course_name,
slp.course_id,
slp.student_type,
slp.stu_reference_id,
COUNT(*) as counttotalWatchedStudents,
SUM(slp.watched_percentage >= 90) as fullwatchedStudentsCount,
SUM(slp.watched_percentage < 90) as stillwatchedStudentsCount
FROM tbl_student_learning_path slp
LEFT JOIN tbl_courses tbc ON tbc.course_pid = slp.course_id
WHERE slp.stu_reference_id = 34
AND slp.student_type= 'institute'
GROUP BY slp.course_id;
MySQL对待true = 1和false = 0,所以你可以简单地总结一下真理: - )