我正在开发一个将表数组转换为JSON的函数,这是我的代码。我检查过strJSON是我想要的JSON格式,但它是一个字符串而不是JSON对象。当我尝试使用“eval”将其转换为JSON时,会显示一条错误消息,提示“Darren未定义”。我不知道发生了什么。
var myArray=[["Name","Age","Gender"],["Darren",31,"Male"],["Gakki",25,"Female"]];
//expected output
var myJSON=[{"Name":"Darren","Age":31,"Gender":"Male"},{"Name":"Gakki","Age":25,"Gender":"Female"}];
function convertJSON(tableData){
var objJSON=[];
var strJSON=[];
tableData.forEach(function(rowData,i){
if (i==0){
rowData.forEach(function(cellData){
head.push(cellData);
});
}
else{
var objData=[];
var objEntry=[];
rowData.forEach(function(cellData,j){
objData=head[j] + ":" + cellData;
objEntry.push(objData);
});
strJSON.push("{" + objEntry + "}");
}
});
objJSON=eval("[" + strJSON + "]");
return objJSON
}
答案 0 :(得分:2)
var myArray=[["Name","Age","Gender"],["Darren",31,"Male"],["Gakki",25,"Female"]];
var properties = myArray.shift();
var result = myArray.map( a => {
var newObj = {};
properties.forEach ( (p, idx) => {
newObj[p] = a[idx];
});
return newObj;
})
console.log(result);
答案 1 :(得分:0)
function html2json() {
var json = '{';
var otArr = [];
var tbl2 = $('#dest_table tr').each(function(i) {
x = $(this).children();
var itArr = [];
x.each(function() {
itArr.push('"' + $(this).text() + '"');
});
otArr.push('"' + i + '": [' + itArr.join(',') + ']');
})
json += otArr.join(",") + '}'
return json;
}
答案 2 :(得分:0)
请勿尝试手动创建JSON字符串。将普通对象放在一起并使用JSON.stringify
进行转换。
var myArray=[["Name","Age","Gender"],["Darren",31,"Male"],["Gakki",25,"Female"]];
//expected output
var myJSON=[{"Name":"Darren","Age":31,"Gender":"Male"},{"Name":"Gakki","Age":25,"Gender":"Female"}];
function convertJSON(tableData){
var keys = tableData[0],
objects = [];
for(var i = 1; i < tableData.length; i++){
var rowObject = {};
tableData[i].forEach(function(item, index){
rowObject[keys[index]] = item;
});
objects.push(rowObject);
}
return JSON.stringify(objects);
}
document.write(convertJSON(myArray));
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