我如何得到＆＃34; nameValuePairs＆＃34;在使用Retrofit的JSON请求中？

Question

如何发布JSONObject请求，如下所示？

原始请求：

    {
        "pObj": [],
        "robj": [
            {
                "l_index": "1",
                "user_id": "111",
                "vername": "1",
                "fcmtoken": "ghkghkhkh"
            }
        ],
        "uobject": [],
        "pname": "y6y68uuy7"
    }

在Volley中我可以成功发布JSONObject请求。但是当我在Retrofit中使用它时，我的请求改变如下：

我在日志中得到的内容：

  {
        "nameValuePairs": {
            "pObj": {
                "values": []
            },
            "robj": {
                "values": [
                    {
                        "nameValuePairs": {
                            "l_index": "1",
                            "user_id": "111",
                            "vername": "1",
                            "fcmtoken": "ghkghkhkh"
                        }
                    }
                ]
            },
            "uobject": {
                "values": []
            },
                    "pname": "y6y68uuy7"
        }
    }

我收到服务器端的错误请求。

我的改造API接口：

public interface ApiInterface {

    @Headers( "Content-Type: application/json; charset=utf-8")
    @POST("re_clientdata")

    Call<String> savePost(@Body JSONObject  req);
}

我的APIClient

public class ApiClient {

    private static Retrofit retrofit = null;

    public static Retrofit getClient(String baseUrl) {
        HttpLoggingInterceptor interceptor = new HttpLoggingInterceptor();
        interceptor.setLevel(HttpLoggingInterceptor.Level.BODY);
        OkHttpClient client = new OkHttpClient.Builder()
                .addInterceptor(interceptor).build();

        if (retrofit==null) {
            retrofit = new Retrofit.Builder()
                    .baseUrl(baseUrl)
                    .client(client)
                    .addConverterFactory(GsonConverterFactory.create())
                    .build();
        }
        return retrofit;
    }
}

MainActivity代码：

protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    sendPost(jRequest);
}

public void sendPost(JSONObject requestobject) {
    Log.e("requestobject",requestobject.toString());

    Call<String> call =mAPIService.savePost(requestobject);
    call.enqueue(new Callback<String>() {
        @Override
        public void onResponse(Call<String>callback,Response<String>response) {
            String res = response.body();
            Log.e("DEMO", "post submitted to API." + response);
        }
        @Override
        public void onFailure(Call<String> call, Throwable t) {
            Log.e("DEMO", "Unable to submit post to API.",t);
            Log.e("call", String.valueOf(call));
        }
    });

}

注意：我也尝试使用HashMap，但会自动添加相同的nameValuePairs参数。如果我使用Gson JsonObject，请在序列化中请求转换。所以我不想在服务器方面做任何改变，因为使用Volley可以正常工作。但现在我想使用相同的请求使用Retrofit。

Answer 1

更改我的APi界面以进行改造

public interface ApiInterface {

    @Headers( "Content-Type: application/json; charset=utf-8")
    @POST("re_clientdata")


    Call<String> savePost(@Body RequestBody req);
}

同时更改此活动代码

protected void onCreate(Bundle savedInstanceState) {

                super.onCreate(savedInstanceState);
                setContentView(R.layout.activity_main);

                 sendPost(jRequest);

        }

        public void sendPost(JSONObject requestobject) {
            Log.e("requestobject",requestobject.toString());

              RequestBody myreqbody = null;
                try {
                     myreqbody = RequestBody.create(okhttp3.MediaType.parse("application/json; charset=utf-8"),
                            (new JSONObject(String.valueOf(requestobject))).toString());
                } catch (JSONException e) {
                    e.printStackTrace();
                }

                Call<String> call =mAPIService.savePost(myreqbody);


            call.enqueue(new Callback<String>() {
                @Override
                public void onResponse(Call<String>callback,Response<String>response) {
                    String res = response.body();
                    Log.e("DEMO", "post submitted to API." + response);
                }
                @Override
                public void onFailure(Call<String> call, Throwable t) {
                    Log.e("DEMO", "Unable to submit post to API.",t);
                    Log.e("call", String.valueOf(call));
                }
            });

        }

  

有关详情，请查看此内容   answer建议    Pratik Vyas 。