我已经编写了一个算法来计算轨道的距离,然后是车辆的一个行程。轨道上的每个点都有一个(纬度,经度)。这是我的代码,我收到了上面提到的错误。
List<TrackPoint> tp = new ArrayList<TrackPoint>();
for (int i = 0; i < tp.size(); i++) {
double lat1 = tp.get(i).getLat();
double lat2 = tp.get(i + 1).getLat();
double lon1 = tp.get(i).getLon();
double lon2 = tp.get(i + 1).getLon();
double radlat1 = Math.PI * lat1 / 180;
double radlat2 = Math.PI * lat2 / 180;
double theta = lon1 - lon2;
double radtheta = Math.PI * theta / 180;
double dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
dist = Math.acos(dist);
dist = dist * 180 / Math.PI;
dist = dist * 60 * 1.1515;
dist = dist * 1609.344;// distance in miles
double _KM = 1000; //KM the unit of distance
//distance in km
double distInKM = dist / _KM;
DecimalFormat df = new DecimalFormat("###.###");
double dt = Double.parseDouble(df.format(distInKM));
double mileage = 0;
mileage += mileage + dt;
tp.get(i).setMileage(mileage);
}
错误:
java.lang.IndexOutOfBoundsException: Index: 283, Size: 283
at java.util.ArrayList.rangeCheck(ArrayList.java:653)
at java.util.ArrayList.get(ArrayList.java:429)
此错误指向行:double lat2 = tp.get(i + 1).getLat();
我认为错误与列表大小有关,但我无法弄清楚为什么?有人帮我看看我有什么不对。
答案 0 :(得分:2)
当您转到循环中的最后一个对象(TrackPoint
)时,i + 1
元素不存在。
double lat2 = tp.get(i + 1).getLat();
答案 1 :(得分:1)
问题出在这里
tp.get(i + 1)
当i
等于tp.size-1
时,您将其等于tp.size()
。要解决它,请将循环更改为:
for (int i = 0; i < tp.size() - 1; i++) {
答案 2 :(得分:0)
当你转到循环中的最后一个对象(TrackPoint)时,第(i + 1)个元素不存在。希望以下代码可以。
List<TrackPoint> tp = new ArrayList<TrackPoint>();
for (int i = 0; i < tp.size()-1; i++) {
double lat1 = tp.get(i).getLat();
double lat2 = tp.get(i + 1).getLat();
double lon1 = tp.get(i).getLon();
double lon2 = tp.get(i + 1).getLon();
double radlat1 = Math.PI * lat1 / 180;
double radlat2 = Math.PI * lat2 / 180;
double theta = lon1 - lon2;
double radtheta = Math.PI * theta / 180;
double dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
dist = Math.acos(dist);
dist = dist * 180 / Math.PI;
dist = dist * 60 * 1.1515;
dist = dist * 1609.344;// distance in miles
double _KM = 1000; //KM the unit of distance
//distance in km
double distInKM = dist / _KM;
DecimalFormat df = new DecimalFormat("###.###");
double dt = Double.parseDouble(df.format(distInKM));
double mileage = 0;
mileage += mileage + dt;
tp.get(i).setMileage(mileage);
}
答案 3 :(得分:0)
循环迭代直到列表大小。但是在最后一次迭代中,你试图得到(i + 1)你的情况下不存在的索引。
double lat2 = tp.get(i + 1).getLat();
纠正这个.get(i + 1)。
答案 4 :(得分:0)
以上所有答案都是正确的。或者可以尝试使用以下代码
List<TrackPoint> tp = new ArrayList<TrackPoint>();
for (int i = 0; i < tp.size(); i++) {
double lat1 = tp.get(i - 1).getLat();
double lat2 = tp.get(i).getLat();
double lon1 = tp.get(i - 1).getLon();
double lon2 = tp.get(i).getLon();
double radlat1 = Math.PI * lat1 / 180;
double radlat2 = Math.PI * lat2 / 180;
double theta = lon1 - lon2;
double radtheta = Math.PI * theta / 180;
double dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
dist = Math.acos(dist);
dist = dist * 180 / Math.PI;
dist = dist * 60 * 1.1515;
dist = dist * 1609.344;// distance in miles
double _KM = 1000; //KM the unit of distance
//distance in km
double distInKM = dist / _KM;
DecimalFormat df = new DecimalFormat("###.###");
double dt = Double.parseDouble(df.format(distInKM));
double mileage = 0;
mileage += mileage + dt;
tp.get(i - 1).setMileage(mileage);
}