这是我的代码。
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
namespace LinkedList
{
public class Node
{
public int data;
public Node next;
public Node(int data)
{
this.data = data;
next = null;
}
}
public class MyList
{
public Node head;
public MyList()
{
head = null;
}
public void addNode(int data)
{
if(head == null)
{
head = new Node(data);
}
else
{
Node temp = new Node(data);
Node current = head;
while(current.next != null)
{
current = current.next;
}
current.next = temp;
}
}
public void print()
{
if(head == null)
{
Console.WriteLine("List is already empty!");
}
else
{
Node current = head;
while (current != null)
{
Console.Write("|" + current.data + "|-> ");
current = current.next;
}
Console.WriteLine();
}
}
public void addToStart(int data)
{
if(head == null)
{
head = new Node(data);
}
else
{
Node temp = new Node(data);
temp.next = head;
head = temp;
}
}
public void addSorted(int data)
{
if(head == null)
{
head = new Node(data);
}
else if(data < head.data)
{
addToStart(data);
}
else
{
Node current = head.next;
Node previous = head;
Node temp = new Node(data);
while(current != null)
{
if(data < current.data)
{
previous.next = temp;
temp.next = current;
break;
}
previous = current;
current = current.next;
}
}
}
public void removeLast()
{
if(head == null)
{
Console.WriteLine("List is already empty!");
}
else if(head.next == null)
{
head = null;
}
else
{
Node current = head.next;
Node previous = head;
while(current.next != null)
{
previous = current;
current = current.next;
}
previous.next = null;
}
}
public bool isPalindrome()
{
List<int> arr1 = new List<int>();
int i = 0;
Node current = head;
while (current != null)
{
arr1.Add(current.data);
current = current.next;
i++;
}
int[] arr3 = arr1.ToArray();
int count = i;
int[] arr2 = new int[count];
int j = 0;
for (int x = i - 1; x >= 0; x--)
{
arr2[j] = arr3[x];
}
for (int k = 0; k < count; k++)
{
if (arr3[k] != arr2[k])
{
return false;
}
}
return true;
}
}
class Program
{
static void Main(string[] args)
{
MyList a = new MyList();
a.addNode(1);
a.addNode(2);
a.addNode(5);
a.addNode(2);
a.addNode(1);
a.print();
if(a.isPalindrome())
{
Console.WriteLine("Linked List is Palindrome!");
}
else
{
Console.WriteLine("Linked List is Not Palindrome!");
}
}
}
}
我的代码每次都为回文函数返回false,除非我在链表中只输入一个值。
另请告诉我,List<int>
的方法是否合适,因为我需要进行回文检查。
答案 0 :(得分:0)
谢谢您的评论,这就是我解决的问题。
public bool isPalindrome()
{
int i = 0;
Node current = head;
Node temp = head;
while (temp != null)
{
temp = temp.next;
i++;
}
int[] arr1 = new int[i];
int count = i;
for (int j = 0; j < count; j++)
{
arr1[j] = current.data;
current = current.next;
}
int[] arr2 = new int[count];
int z = 0;
for (int x = i - 1; x >= 0; x--)
{
arr2[z] = arr1[x];
z++;
}
for (int x = 0; x < count; x++)
{
if (arr1[x] != arr2[x])
{
return false;
}
}
return true;
}