Question

我有来自供应商的这个xml（摘录）：

<Roles xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:immutable="http://www.digitalmeasures.com/schema/immutable">
    <immutable:Role roleKey="INDIVIDUAL-ACTIVITIES-University-DataBackupService" text="Data Backup Service">
        <Item xlink:type="simple" xlink:href="/login/service/v4/Role/INDIVIDUAL-ACTIVITIES-University-DataBackupService"/>
        <Users xlink:type="simple" xlink:href="/login/service/v4/RoleUser/INDIVIDUAL-ACTIVITIES-University-DataBackupService"/>
    </immutable:Role>
    <Role roleKey="INDIVIDUAL-ACTIVITIES-University-DepartmentUpdatePrimaryAssignmentOrg" text="Department: Update Primary Assignment Org">
        <Item xlink:type="simple" xlink:href="/login/service/v4/Role/INDIVIDUAL-ACTIVITIES-University-DepartmentUpdatePrimaryAssignmentOrg"/>
        <Users xlink:type="simple" xlink:href="/login/service/v4/RoleUser/INDIVIDUAL-ACTIVITIES-University-DepartmentUpdatePrimaryAssignmentOrg"/>
    </Role>
</Roles>

我在c＃代码中设置了这些类：

public class Role
{
    [XmlAttribute]
    public string roleKey { get; set; }
    [XmlAttribute]
    public string text { get; set; }
    [XmlAttribute]
    public string Item { get; set; }
    [XmlAttribute]
    public string Users { get; set; }
}

//Class to hold our array of <DailyStat>
[Serializable]
[XmlRootAttribute("Roles")]
//[XmlRootAttribute("immutable:Roles")]
public class Roles
{
    [XmlElement("Role")]
    public Role[] thisRole { get; set; }
}

我从供应商处获得的xml（通过Web服务）有20个标记为Role的元素，6个标记为immutable：Role。当我运行我的代码时，我只看到20个角色项目，但我想要所有26个项目。我怎样才能得到它们？

Answer 1

我为类生成选择的武器是xsd，我发现控制这样的属性要容易得多，而不是自己生成它们，特别是在像你这样的棘手场景中。基本上，它是两个名称空间的故事。结构相同，属性装饰不同。有两个不同的命名空间no和imm来分隔Role类。 Item和Users个节点具有CT常见类型，no.Role和imm.Role共享此类型。

internal static class ct
{
 public const string nsImmutable = "http://www.digitalmeasures.com/schema/immutable";
 public const string nsXLink = "http://www.w3.org/1999/xlink";
}

[Serializable]
[XmlType(AnonymousType = true)]
[XmlRoot(Namespace = "", IsNullable = false)]
public partial class Roles
{
  [XmlElement("Role", typeof(no.Role))]
  [XmlElement("Role", typeof(imm.Role), Namespace = ct.nsImmutable)]
  public object[] Items { get; set; }
}

public partial class BaseRole
{
  [XmlAttribute("roleKey")]
  public string RoleKey { get; set; }

  [XmlAttribute("text")]
  public string Text { get; set; }
}

  [Serializable]
  [XmlType(AnonymousType = true)]
  //[XmlRoot(Namespace = "", IsNullable = false)]
  public partial class CT
  {
    [XmlAttribute(Form = XmlSchemaForm.Qualified, Namespace = ct.nsXLink, AttributeName = "type")]
    public string Type { get; set; }

    [XmlAttribute(Form = XmlSchemaForm.Qualified, Namespace = ct.nsXLink, AttributeName = "href")]
    public string Href { get; set; }
  }

namespace imm
{
  [Serializable]
  [XmlType(AnonymousType = true, Namespace = ct.nsImmutable)]
  [XmlRoot(Namespace = ct.nsImmutable, IsNullable = false)]
  public partial class Role : BaseRole
  {
    [XmlElement(Namespace = "", Type = typeof(CT), ElementName = "Item")]
    public CT Item { get; set; }

    [XmlElement(Namespace = "", Type = typeof(CT), ElementName = "Users")]
    public CT Users { get; set; }
  }      
}


namespace no
{
  [Serializable]
  [XmlType(AnonymousType = true)]
  public partial class Role : BaseRole
  {
    [XmlElement("Item", typeof(CT))]
    public CT Item { get; set; }

    [XmlElement("Users", typeof(CT))]
    public CT Users { get; set; }
  }
}

Answer 2

只是将其发布给其他人，我发现这个网站将xml转换为c＃对象。我喜欢的结果比Paste Special更好 - ＆gt;将XML粘贴为Classes给了我。 XML to c# website

来自供应商的C＃ - xml具有同一对象的多个元素名称。如何将它们序列化为同一个对象？

2 个答案: