Question

我正在使用transact SQL，我得到了这些表......

main.locality - id,locality
main.job - id,jobs
main.person - name,surname,jobid,localityid,salary,gender

我需要获得此输出（XML RAW）PS。第一行是所有工作的平均工资第二行是所有女性的平均工资第三行是所有男性的平均工资第四行是该工作和女性的平均工资第五行是该工作和男性的平均工资

<row Average="19827" /> 
<row gender="F" Average="19835" /> 
<row gender="M" Average="19819" /> 
<row job="C# Developer" Average="20941" /> 
<row job="C# Developer" gender="F" Average="20845" />
<row job="C# Developer" gender="M" Average="21027" />

有人可以帮我查询吗？

Answer 1

我在想：

-- 1. SAMPLE DATA
DECLARE @locality TABLE (localityid int, locality int);
DECLARE @job TABLE (id int, Job varchar(100));
DECLARE @person TABLE 
(
  name varchar(100), 
  surname varchar(100),
  jobid int,
  localityid int,
  salary money,
  gender char(1)
);

INSERT @locality VALUES (1, 10), (2, 20), (3, 35), (4, 1000);
INSERT @job VALUES (1, 'C# Developer'), (2, 'DBA');
INSERT @person VALUES 
('joe', 'blow', 1, 1, 100000, 'M'),
('Sally', 'Doe', 1, 2, 135000, 'F'),
('Sue', 'Smith', 2, 2, 115000, 'F'),
('Kyle', 'Jones', 2, 3, 107500, 'M')
; 

-- 2. SOLUTION:
SELECT gender = NULL, job = NULL, average = AVG(p.salary)
FROM @person p
UNION ALL
SELECT p.gender, job = NULL, average = AVG(p.salary) 
FROM @person p
JOIN @job j ON p.jobid = j.id
GROUP BY p.gender
UNION ALL
SELECT gender = NULL, job = j.job, average = AVG(p.salary) 
FROM @person p
JOIN @job j ON p.jobid = j.id
GROUP BY j.Job
UNION ALL
SELECT p.gender, j.Job, average = AVG(p.salary)
FROM @person p
JOIN @job j ON p.jobid = j.id
GROUP BY p.gender, j.Job
FOR XML RAW;

返回：

<row average="114375.0000" />
<row gender="F" average="125000.0000" />
<row gender="M" average="103750.0000" />
<row job="C# Developer" average="117500.0000" />
<row job="DBA" average="111250.0000" />
<row gender="F" job="C# Developer" average="135000.0000" />
<row gender="M" job="C# Developer" average="100000.0000" />
<row gender="F" job="DBA" average="115000.0000" />
<row gender="M" job="DBA" average="107500.0000" />

Answer 2

这是a job for ROLLUP

（我借用了Alan Burstein的样本数据 - 谢谢！）

-- 1. SAMPLE DATA
DECLARE @locality TABLE (localityid int, locality int);
DECLARE @job TABLE (id int, Job varchar(100));
DECLARE @person TABLE 
(
  name varchar(100), 
  surname varchar(100),
  jobid int,
  localityid int,
  salary money,
  gender char(1)
);

INSERT @locality VALUES (1, 10), (2, 20), (3, 35), (4, 1000);
INSERT @job VALUES (1, 'C# Developer'), (2, 'DBA');
INSERT @person VALUES 
('joe', 'blow', 1, 1, 100000, 'M'),
('Sally', 'Doe', 1, 2, 135000, 'F'),
('Sue', 'Smith', 2, 2, 115000, 'F'),
('Kyle', 'Jones', 2, 3, 107500, 'M');


SELECT j.Job
      ,p.gender 
      ,AVG(p.salary) AS Average 
FROM @person AS p
INNER JOIN @locality AS l ON p.localityid=l.localityid
INNER JOIN @job AS j ON p.jobid=j.id
GROUP BY ROLLUP (gender,job)
ORDER BY job,gender
FOR XML RAW

结果

<row Average="114375.0000" />
<row gender="F" Average="125000.0000" />
<row gender="M" Average="103750.0000" />
<row Job="C# Developer" gender="F" Average="135000.0000" />
<row Job="C# Developer" gender="M" Average="100000.0000" />
<row Job="DBA" gender="F" Average="115000.0000" />
<row Job="DBA" gender="M" Average="107500.0000" />

查询XML RAW

2 个答案: