Question

再次感谢Gurwinder Singh的帮助。真的很感激。我正在编辑我的样本数据记录，并希望解决问题。

    CREATE TABLE #TEMP
    (
    PER_ID INT,
    PER_SS VARCHAR (11),
    CHARGE_CD VARCHAR (25),
    PER_CODE VARCHAR (20),
    FILE_DT DATETIME,
    PER_CASE_ID INT,
    PER_PS VARCHAR (5),
    CREATE_DT DATETIME


    )

    INSERT INTO #TEMP VALUES('6385789','9801745','21 B 1325(Q)(4)','NMT785989','11/11/2016 12:00 AM','957800','IDA','11/12/2016 11:00 PM')
    INSERT INTO #TEMP VALUES('6385789','9801745','21 B 1325(Q)(4)','NMT785989','11/11/2016 12:00 AM','698080','QBC','11/12/2016 11:00 PM')
    INSERT INTO #TEMP VALUES('6388788','9801746','21 B 1325(Q)(4)','NMT785990','11/11/2016 12:00 AM','957801','CAN','11/12/2016 11:00 PM')
    INSERT INTO #TEMP VALUES('6388788','9801746','21 B 1326(Q)(5)','NMT785990','11/11/2016 12:00 AM','698081','ADA','11/12/2016 11:00 PM')
    INSERT INTO #TEMP VALUES('6385790','9858888','21 B 1326(Q)(5)','NMT785990','11/11/2016 12:00 AM','698888','ADA','11/12/2016 11:00 PM')
    INSERT INTO #TEMP VALUES('6385790','9858888','21 B 1326(Q)(5)','NMT785990','11/11/2016 12:00 AM','698888','CAN','11/12/2016 11:00 PM')



    SELECT 
--the case station with partition script was written by Gurwinder Singh.
    CASE WHEN MAX(PER_ID) OVER (PARTITION BY PER_ID) = MIN(PER_ID) OVER (PARTITION BY PER_ID) THEN 'YES' ELSE 'NO' END AS SAME_PER_ID,
    CASE WHEN MAX(PER_SS) OVER (PARTITION BY PER_ID) = MIN(PER_SS) OVER (PARTITION BY PER_ID) THEN 'YES' ELSE 'NO' END AS SAME_PER_SS,
    CASE WHEN MAX(CHARGE_CD) OVER (PARTITION BY PER_ID) = MIN(CHARGE_CD) OVER (PARTITION BY PER_ID) THEN 'YES' ELSE 'NO' END AS SAME_CHARGE_CD,
    CASE WHEN MAX(PER_CODE) OVER (PARTITION BY PER_ID) = MIN(PER_CODE) OVER (PARTITION BY PER_ID) THEN 'YES' ELSE 'NO' END AS SAME_PER_CODE,
    CASE WHEN MAX(FILE_DT) OVER (PARTITION BY PER_ID) = MIN(FILE_DT) OVER (PARTITION BY PER_ID) THEN 'YES' ELSE 'NO' END AS SAME_PER_FILE_DT,
    PER_ID, 
    PER_SS, 
    CHARGE_CD,
    PER_CASE_ID,
    PER_PS,
    PER_CODE,
    FILE_DT
    FROM #TEMP

有没有办法可以过滤掉两条记录PER_CASE_ID =（698888）。基本上，我对返回这两条记录不感兴趣，因为PER_CASE_ID是相同的。我只对PER_CASE_ID不同的结果感兴趣。再次感谢。乔。

Answer 1

我猜你想显示一组列的不同行中的per_id是否有不同的值。您可以使用窗口函数MIN和MAX来检查相同per_id的不同列中是否存在多个不同的值。

select 
    t.*,
    case when max(PER_SS) over (partition by per_id) = min(PER_SS) over (partition by per_id) then 'Yes' else 'No' end as same_per_ss,
    case when max(PER_MISC) over (partition by per_id) = min(PER_MISC) over (partition by per_id) then 'Yes' else 'No' end as same_per_misc,
    case when max(PER_CLASS) over (partition by per_id) = min(PER_CLASS) over (partition by per_id) then 'Yes' else 'No' end as same_per_class,
    case when max(FILE_DT) over (partition by per_id) = min(FILE_DT) over (partition by per_id) then 'Yes' else 'No' end as same_per_file_dt
from #temp t;

Answer 2

也许你可以尝试从表到自己进行内部联接。类似的东西：

SELECT * FROM TEMP T1 INNER JOIN TEMP T2 ON T1.PER_SS = T2.PER_SS AND T1.PER_ID = T2.PER_ID - etc。

您也可以尝试这样的事情。

SELECT T1。* FROM TEMP T1，TEMP T2 WHERE T1.PER_SS = T2.PER_SS AND T1.PER_ID = T2.PER_ID - etc。

SQL Sever中的Case语句用于标识可能的重复项

2 个答案: