使用dapper.NET C#

时间:2017-05-16 13:52:17

标签: c# sql list dapper

我想在SQL表中插入对象列表。

我知道这个问题here,但我不明白。

这是我的班级:

public class MyObject 
{
    public int? ID { get; set; }
    public string ObjectType { get; set; }
    public string Content { get; set; }
    public string PreviewContent { get; set; }

    public static void SaveList(List<MyObject> lst)
    {
        using (DBConnection connection = new DBConnection())
        {
            if (connection.Connection.State != ConnectionState.Open)
                connection.Connection.Open();

            connection.Connection.Execute("INSERT INTO [MyObject] VALUE()",lst);                
        }
    }
}

我想知道如何使用Dapper插入我的列表,我不想迭代列表并逐个保存,我想在一个请求中插入所有这些

5 个答案:

答案 0 :(得分:11)

您可以像插入一行一样插入这些:

public class MyObject 
{
    public int? ID { get; set; }
    public string ObjectType { get; set; }
    public string Content { get; set; }
    public string PreviewContent { get; set; }

    public static void SaveList(List<MyObject> lst)
    {
        using (DBConnection connection = new DBConnection())
        {
            if (connection.Connection.State != ConnectionState.Open)
                connection.Connection.Open();

            connection.Connection.Execute("INSERT INTO [MyObject] (Id, ObjectType, Content, PreviewContent) VALUES(@Id, @ObjectType, @Content, @PreviewContent)", lst);                
        }
    }
}

Dapper将查找以SQL参数命名的类成员(@ Id,@ ObjectType,@ Content,@ PreviewContent)并相应地绑定它们。

答案 1 :(得分:1)

您需要传递一个表值参数 1.在sql数据库中创建表类型 2.创建DynamicParameters并将数据表(新值)添加到其中 3.执行。

SQL:

CREATE TYPE [dbo].[tvMyObjects] AS TABLE(
    [ID] INT,
    [ObjectType] [varchar](70), /*Length on your table*/
    [Content] [varchar](70), /*Length on your table*/
    [PreviewContent] [varchar](70) /*Length on your table*/
)

C#:

var dynamicParameters = new DynamicParameters();
dynamicParameters.Add("@MyObjects", lst
    .AsTableValuedParameter("dbo.tvMyObjects", new[] 
    {
        "ID" ,
        "ObjectType",
        "Content", 
        "PreviewContent"
    }));

connection.Connection.Execute(@"
    INSERT INTO [MyObject] (Id, ObjectType, Content, PreviewContent) 
    SELECT Id,
           ObjectType,
           Content,
           PreviewContent
    FROM   @MyObjects", dynamicParameters);

更多信息:https://www.codeproject.com/Articles/835519/Passing-Table-Valued-Parameters-with-Dapper

答案 2 :(得分:0)

您只需将SQL更改为有效的插入参数,其参数与您类的属性名称相匹配。

INSERT INTO MyObject VALUES(@Id, @ObjectType, @Content, @PreviewContent)

或者,如果您需要指定表格列(例如,这些列不是表格中的所有列):

INSERT INTO MyObject (Id, ObjectType, Content, PreviewContent)
VALUES(@Id, @ObjectType, @Content, @PreviewContent)

答案 3 :(得分:0)

您可以使用Dapper.Contrib扩展来简化代码。我发现这适用于几百条记录,但对于非常大的插入,我切换到SqlBulkCopy。同步版本是Insert而不是InsertAsync(正如您所猜测的那样)。确保您的实体被命名为Dapper期望并拥有主键,Id,或者为您的实体添加表名和密钥的注释。

using using Dapper.Contrib.Extensions; //Git

public async Task SaveChangesAsync(IList<MyEntity> myEntityValues)
{
     var conn = new SqlConnection(myconnectionString);
     if(conn.State != ConnectionState.Open)
         conn.Open();
     await conn.InsertAsync(myEntityValues);
     if (conn.State != ConnectionState.Closed)
     {
        conn.Close();
        conn.Dispose();
      }
}

答案 4 :(得分:0)

如果您需要新的命名或组合来源:

await connection.ExecuteAsyncWithRetry(SqlSave,
     list.Select(x => 
            new
            {
                x.ID,
                SomeNew = NewSource.SomeNew,  // From other source
                NameNew = x.NameOld,  // New naming
                x.ObjectType,
                x.Content,
                x.ContentList = String.Join(",", x.Content)  // Data transform
            }));