在Python中使用从字符串中删除\ xa0

Question

我有一个价格清单，我希望从中移除所有空格，例如prices[0] = '2673.00'

prices = ['2 673.00', '53.55', '1 478.00', ... ]
prices = [float(x) for x in prices]

我尝试了各种选择，但没有一个适合我。

x = str(prices[0]).replace(' ', '') # Got error --> ValueError: could not convert string to float: '2\xa0673.00'

import unicodedata
my_str = unicodedata.normalize("NFD", str(prices[0])) # tried  ‘NFC’, ‘NFKC’, ‘NFD’, and ‘NFKD’ as different forms but got same error as above

x = str(prices[0]).replace(u'\xa0', u'')  # Got error --> ValueError: could not convert string to float: '2\xa0673.00'

请建议一种可行的方法。感谢。

Answer 1

如果给出了输入，这肯定会起作用：

import re
regexp = re.compile(r'\s+', re.UNICODE)
prices_norm = [regexp.sub('', p) for p in prices]

但更好的解决方案是不要用空格打印浮点数。只需在打印前更改locale：

import locale
locale.setlocale(locale.LC_ALL, 'en_US')