Question

我有一个营业日期。我想要创建已经获得的期票：

day=1
month= the next month of operation_date
year= automatic

示例：

operation_date = 15/11/2010 
promissory_note1_date = 1/12/2010
promissory_note2_date = 1/01/2011
promissory_note3_date = 1/02/2011
promissory_note4_date = 1/02/2011

如果存在四张期票

我怎么能做到？

PD：对不起我的语法

Answer 1

你可以做到

require "active_support"

Date.today.at_beginning_of_month
#=> Wed, 01 Dec 2010

Date.today.at_beginning_of_month.next_month
#=> Sat, 01 Jan 2011

Date.today.at_beginning_of_month.next_month.next_month
#=> Tue, 01 Feb 2011

等等......

Answer 2

如果你没有使用rails或者不想要active_support，我发现没有active_support的更简单方法

(Date.today - Date.today.mday + 1) # First day of the current month
=> Thu, 01 Dec 2016

希望这有帮助！： - ）

Answer 3

我正在使用带有1.8.7的{{1}}和1.9.2，rvm会导致错误：

Date.today

我应该使用ruby-1.8.7-p302 > Date.today NameError: uninitialized constant Date ruby-1.9.2-p0 > Date.today NameError: uninitialized constant Object::Date 这个链接可以帮助你http://pleac.sourceforge.net/pleac_ruby/datesandtimes.html。

我不确定ruby中Time.now方法的可用性，但它确实存在于RoR中。

Answer 4

N个月的一般回复

(Date.today + N.months).at_beginning_of_month

Answer 5

我的解决方案：

class Time
  def start_of_next_month
    Time.local(self.year + self.month / 12, self.month % 12 + 1)
  end
end

Answer 6

对于那些使用Time类的人：

class Time
        def start_of_next_month
                t = Time.local(self.year,self.month)+45*24*3600;
                Time.local(t.year,t.month)
        end
end

我知道这有点笨拙:)。

Answer 7

我想获得一年中的第一个星期一（用于导轨装置），以下工作：

Date.new(Date.today.year,1,1).beginning_of_week

如果您不在轨道中，则可能如下所示，

# get the last day of the previous year
d = Date.new(Date.today.year - 1,12,31)
# advance to the next monday. This relies on w.day being 0..6, where 0 is sunday.
first_monday = d + (8 - d.wday).days

Answer 8

截至2017年11月，最新版本不再支持for (index, dict) in self.appDelegate.arrayOfDictionary.enumerated() { for element in dict { if element.key == "sellingPrice" { let PAinTxtField = alertController.textFields?.first?.text)! var thePA = (Int(PAinTxtField ) ?? 0) //This is partial amount let theSP = (Int("\(element.value)") ?? 0) //This is selling price if thePA < theSP { self.remainingAmt = theSP - thePA var dictCopy = dict dictCopy["remaining_balance"] = "\(self.remainingAmt)" //The mistake seems to be because of this line. But cannot figure out what exactly...:( } } } }。考虑到您使用的是Rails，可以使用at_beginning_of_month

Answer 9

ActiveSupport似乎有点重量级加载。我会这样做：

require 'date'
first = Date.new(Date.today.year, Date.today.month, 1)
4.times do |m|
  puts "Promissory note due on #{first >> (m + 1)}"
end

Answer 10

 (DateTime.now.beginning_of_year..DateTime.now.end_of_year).to_a.select {|k| k if k == k.beginning_of_month}
=> [Wed, 01 Jan 2020 00:00:00 +0530, Sat, 01 Feb 2020 00:00:00 +0530, Sun, 01 Mar 2020 00:00:00 +0530, Wed, 01 Apr 2020 00:00:00 +0530, Fri, 01 May 2020 00:00:00 +0530, Mon, 01 Jun 2020 00:00:00 +0530, Wed, 01 Jul 2020 00:00:00 +0530, Sat, 01 Aug 2020 00:00:00 +0530, Tue, 01 Sep 2020 00:00:00 +0530, Thu, 01 Oct 2020 00:00:00 +0530, Sun, 01 Nov 2020 00:00:00 +0530, Tue, 01 Dec 2020 00:00:00 +0530]

Answer 11

如果您在Rails App中尝试使用extended_date这个宝石，则变得很容易。这将帮助我们获得一个月中任何一天的首次出现

Date.today.first_day_of_month("friday") Date.today.first_day_of_month(5) Date.today.first_day_of_month(0)

如何获得红宝石下个月的第一天？

11 个答案: