TITLE:VAL
TITLE:VAL2
等。我尝试使用HTML换行标记,但这不起作用。有什么建议?这是现在的输出:https://gyazo.com/f98de4fc8941874aea27ad03750f6955?token=981b91ccbeae94c64a15b76e654708b9
<!DOCTYPE html>
<html>
<body>
<div id="XMLDisplay">
<p id="container"></p>
</div>
<script>
var paragraph = document.getElementById("container");
var xmlhttp, xmlDoc;
xmlhttp = new XMLHttpRequest();
xmlhttp.open("GET", "Opdracht1XML.xml", false);
xmlhttp.send();
xmlDoc = xmlhttp.responseXML;
x = xmlDoc.getElementsByTagName("CD")[0].childNodes;
z = xmlDoc.getElementsByTagName("CD")
for (k = 0; k < x.length; k++) {
y = xmlDoc.getElementsByTagName("CD")[k].firstChild;
for (i = 0; i < x.length; i++) //looping xml childnodes
{
if (y.nodeType == 1) {
var elements = y.nodeName;
var values = y.firstChild.nodeValue;
paragraph.append(elements + ": " + values);
}
y = y.nextSibling;
}
document.write("<br/>");
}
</script>
</body>
</html>
答案 0 :(得分:0)
我自己找到了解决方案,谢谢你自己努力寻找解决方案!
(溶液:
<script>
var xmlhttp = new XMLHttpRequest();
xmlhttp.onreadystatechange = function() {
if (this.readyState == 4 && this.status == 200) {
myFunction(this);
}
};
xmlhttp.open("GET", "Opdracht1XML.xml", true);
xmlhttp.send();
function myFunction(xml) {
var i;
var xmlDoc = xml.responseXML;
var table="<tr><th>Title</th><th>Artist</th><th>Country</th><th>Company</th><th>Price</th><th>Year</th></tr>";
var x = xmlDoc.getElementsByTagName("CD");
for (i = 0; i <x.length; i++) {
table += "<tr><td>" +
x[i].getElementsByTagName("TITLE")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("ARTIST")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("COUNTRY")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("COMPANY")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("PRICE")[0].childNodes[0].nodeValue +
"</td><td>" +
x[i].getElementsByTagName("YEAR")[0].childNodes[0].nodeValue +
"</td></tr>";
}
document.getElementById("table").innerHTML = table;
}
</script>
)