Question

我已经推出了IE 11浏览器，

我已导航到初始网址 - ＆gt;完成鼠标并点击链接 - ＆gt;它会重定向到另一个页面。

在该页面中，我必须单击一个按钮，但它会抛出异常

org.openqa.selenium.NoSuchWindowException：无法在关闭的窗口中找到元素

但是屏幕仍然可用。

这是我的代码

WebElement e = driver.findElement（By.xpath（“html / body / div [2] / div / div / header / nav / ul / li [2] / a”））;

    Actions a = new Actions(driver);
    a.moveToElement(e).build().perform();

    driver.findElement(By.xpath("//*[@id='menu-item-35']/a")).click();



  TimeUnit.SECONDS.sleep(5);

//此后发生异常，但是当我删除下面的代码时，测试用例传递

driver.findElement(By.xpath("//*[@id='default_products_page_container']/div[3]/div[2]/form/div[2]/div[1]/span/input")).click();

这是页面的网址：http://store.demoqa.com/

Answer 1

在我看来，这是一个竞争条件错误。我自己有这些情况，我实际上可以看到一个窗口，但Selenium仍然说它不在那里。

您是否尝试将睡眠时间设置为更高的值？

您也可以尝试在点击元素之前设置expect-wait-condition。

    WebDriverWait wait = new WebDriverWait(DRIVER, 20);
    wait.until(ExpectedConditions.elementToBeClickable(By.xpath("//*[@id='default_products_page_container']/div[3]/div[2]/form/div[2]/div[1]/span/input"))

Answer 2

Here is the Solution to your Question:

A few words about the solution:

The xpath html/body/div[2]/div/div/header/nav/ul/li[2]/a looks petty vulnerable to me use linkText locator.
Once you use Action Class to build().perform(), induce a bit of wait before locating another element.
Instead of xpath locator of //*[@id='menu-item-35']/a element, use linkText locator.
Again the xpath //*[@id='default_products_page_container']/div[3]/div[2]/form/div[2]/div[1]/span/input looks petty vulnerable to me use a logical uniquexpath.

Here is your own working code block with some simple tweaks in it:

driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
WebElement e = driver.findElement(By.linkText("Product Category"));
Actions a = new Actions(driver);
a.moveToElement(e).build().perform();
driver.findElement(By.linkText("iMacs")).click();
driver.findElement(By.xpath("//input[@name='Buy']")).click();

Let me know if this Answers your Question.

NoSuchWindowException - Selenium 3.4.0 - IE 11

2 个答案: