Question

我想在事务表中使用mongo mapper起诉聚合框架管道，结果应该是这样的：假设我在status 1,2,3,4 (1=pending, 2=confirmed, 3=decline, 4=claimed)

的集合中有7000个事务

数据表示：

Pending Count | Confirmed Count | Decline Count | Claimed Count
 4000                 2000            1000          0

1。问题是我不确定哪个字段应该用于组中的密钥。

我的代码将返回符合条件的所有记录。

请看一下我的代码：

$filters = array('dateCreated'=>array(
                            '$gte'=>'2015-01-01', 
                            '$lte'=>'2017-05-15'
                    ));

 $group = [
              'keys' =>['userId'=>1],
              'initial' => ['pendingCount'=>0, 'confirmedCount'=>0, 'declineCount'=>0, 'claimedCount'=>0],
              'reduce'=>'
                      function(obj, result){

                        switch(result.status){
                            case 1:
                                result.pendingCount++;
                                break;

                            case 2:
                                result.confirmedCount++;
                                break;                          

                            case 3:
                                result.declineCount++;
                                break;
                            case 4:
                                result.claimedCount++;
                                break;

                        }
                      }
                        ',
              'finalize'=>'function(result){}'
        ];

 $data =  $this->mapper->find($filter, ['group'=>$group]);
 echo "data<pre>";
 print_r($data);

输出：

在这里，您看到它返回了多个文档，但我只想要一条记录用于所有事务，可能是键userId应该替换为“null”

阵列（ [0] =＆gt;排列（ [_id] =＆gt; MongoId对象（ [$ id] =＆gt; 591a8f5bb06b243d0262d0a1 ）

        [userId] => 
        [pendingCount] => 0
        [confirmedCount] => 0
        [declineCount] => 0
        [claimedCount] =>0
    )

[1] => Array
    (
        [_id] => MongoId Object
            (
                [$id] => 591a8f5bb06b243d0262d0a2
            )

        [userId] => 
        [pendingCount] => 0
        [confirmedCount] => 0
        [declineCount] => 0
        [claimedCount] =>0
    )

[2] => Array
    (
        [_id] => MongoId Object
            (
                [$id] => 591a8f5bb06b243d0262d0a3
            )

        [userId] => 38730976
        [pendingCount] => 0
        [confirmedCount] => 0
        [declineCount] => 0
        [claimedCount] =>0
    )

[3] => Array
    (
        [_id] => MongoId Object
            (
                [$id] => 591a8f5bb06b243d0262d0a4
            )

        [userId] => 64920
        [pendingCount] => 0
        [confirmedCount] => 0
        [declineCount] => 0
        [claimedCount] =>0
    )

...

Answer 1

您按//*[starts-with(name(), 'h')]进行分组，因此每userId行可获得一行。只需传递一个空的userId数组来聚合所有记录的数据。你的缩减函数也有一个拼写错误：它应该是keys：

obj.status

php f3框架使用聚合框架管道与mongo mapper

1 个答案: