我正在使用Android Studio,我想使用Google API作为登录信息。如果登录成功,则可以更改为其他活动。除此之外,我想在另一个活动中显示帐户名称和个人资料图片,但是我收到了这个错误:
错误:标识符期望GoogleApiClient = new GoogleApiClient.Builder(this).enableAutoManage(this,this).addApi(Auth.GOOGLE_SIGN_IN_API,gso).build();
我的代码:
package com.example.alif.angkotcoba;
import android.content.Intent;
import android.support.annotation.NonNull;
import android.support.v7.app.AppCompatActivity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import com.google.android.gms.auth.api.Auth;
import com.google.android.gms.auth.api.signin.GoogleSignInAccount;
import com.google.android.gms.auth.api.signin.GoogleSignInOptions;
import com.google.android.gms.auth.api.signin.GoogleSignInResult;
import com.google.android.gms.common.ConnectionResult;
import com.google.android.gms.common.SignInButton;
import com.google.android.gms.common.api.GoogleApiClient;
public class MainActivity extends AppCompatActivity implements
View.OnClickListener,GoogleApiClient.OnConnectionFailedListener {
private SignInButton SignIn;
private GoogleApiClient GoogleApiClient;
private static final int RC_SIGN_IN =9001;
private static final String TAG ="signInActivity";
GoogleSignInOptions gso=new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
.requestIdToken(getString(R.string.default_web_client_id))
.requestEmail()
.build();
GoogleApiClient = new GoogleApiClient.Builder(this).enableAutoManage(this,this).addApi(Auth.GOOGLE_SIGN_IN_API, gso).build();
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
SignIn = (SignInButton) findViewById(R.id.btngoogle);
SignIn.setOnClickListener(this);
}
public void gotoSecondActivity (View view) {
Intent intent = new Intent(this, SecondActivity.class);
startActivity(intent);
}
@Override
public void onClick(View v) {
switch (v.getId()) {
case R.id.btngoogle:
signIn ();
break;
}
}
public void signIn ()
{
Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(GoogleApiClient);
startActivityForResult(signInIntent, RC_SIGN_IN);
}
public void handleResult (GoogleSignInResult result) {
GoogleSignInAccount account = result.getSignInAccount();
String name = account.getDisplayName();
String email = account.getEmail();
String img_url = account.getPhotoUrl().toString();
}
@Override
public void onActivityResult(int requestcode,int resultcode,Intent data) {
super.onActivityResult(requestcode,resultcode,data);
if (requestcode==RC_SIGN_IN){
GoogleSignInResult result=Auth.GoogleSignInApi.getSignInResultFromIntent(data);
handleSignInResult(result);
}
}
private void handleSignInResult(GoogleSignInResult result) {
Log.d(TAG,"handleSignInResult:"+ result.isSuccess());
if (result.isSuccess()){
Intent intent = new Intent(this, SecondActivity.class);
startActivity(intent);
}
}
@Override
public void onConnectionFailed(@NonNull ConnectionResult connectionResult) {
Log.d(TAG,"onConnectionFailed:"+connectionResult);
}
}
答案 0 :(得分:0)
您需要在声明中使用变量名称。问题是你试图声明一个与类同名的变量:
private GoogleApiClient GoogleApiClient;
那不会奏效。就编译器而言,分配左侧的所有内容都是类型名称GoogleApiClient
。尝试这样的事情:
private GoogleApiClient googleApiClient; // note change of case!
googleApiClient = ...
此外,您最好初始化依赖于this
内的onCreate
而不是声明变量的任何内容。