Question

我正在为棋盘游戏制作超级简单的服务器。它得到一个客户端连接，为我创建的Board对象创建输入流并将其发回。每当我在服务器或客户端中调用readObject时，我都会收到java.lang.ClassNotFoundException错误。造成这种情况的原因是什么？

SERVER SOCKET

import java.net.*;
import java.io.*;

public class GreetingServer extends Thread {
   private ServerSocket serverSocket;

   public GreetingServer(int port) throws IOException {
      serverSocket = new ServerSocket(port);
      //serverSocket.setSoTimeout(10000);  //Don't timeout
   }

   public void run() {
      while(true) {
         try {
            PlayerBoard board;
            System.out.println("Waiting for client on port " + 
               serverSocket.getLocalPort() + "...");
            Socket server = serverSocket.accept();

            System.out.println("Just connected to " + server.getRemoteSocketAddress());
            ObjectInputStream in = new ObjectInputStream(server.getInputStream());

            //Get PlayerBoard Object from server.
            board = (PlayerBoard)in.readObject();      //LINE THAT GIVES ME EXCEPTION

            //Send PlayerBoard back
            ObjectOutputStream out = new ObjectOutputStream(server.getOutputStream());
            out.writeObject(board);

            //Close server
            server.close();

         }catch(SocketTimeoutException s) {
            System.out.println("Socket timed out!");
            break;
         }catch(IOException e) {
            e.printStackTrace();
            break;
         }
      }
   }

   public static void main(String [] args) {
      int port = 25565;
      try {
         Thread t = new GreetingServer(port);
         t.start();
      }catch(IOException e) {
         e.printStackTrace();
      }
   }
}

CLIENT SOCKET

import apcslib.*;
import java.net.*;
import java.io.*;

public class GreetingClient {

   public static void main(String [] args) {
      String serverName = "76.88.3.218";
      PlayerBoard board;
      int port = 25565;
      try {
         System.out.println("Connecting to " + serverName + " on port " + port);
         Socket client = new Socket(serverName, port);

         System.out.println("Just connected to " + client.getRemoteSocketAddress());
         OutputStream outToServer = client.getOutputStream();
         ObjectOutputStream out = new ObjectOutputStream(outToServer);

         //Send server PlayerBoard object
         out.writeObject(new PlayerBoard());

         InputStream inFromServer = client.getInputStream();
         ObjectInputStream in = new ObjectInputStream(inFromServer);

         //Get PlayerBoard object back from server
         board = (PlayerBoard)in.readObject(); //LINE THAT GIVES ME EXCEPTION

         /*Loop to print out board to console
         System.out.println("Board:");
         System.out.print("   ");

         for(int y = 1; y <= board.getWidth(); y++)
         {
            System.out.print(y + " ");
         }
         System.out.println();
         for(int y = 0; y < board.getHeight(); y++)
         {
            System.out.print(Format.left(y+1, 3));
            for (int x = 0; x < board.getWidth(); x++)
               System.out.print(board.displaySpot(x, y) + " ");
            System.out.println();
         }*/

         //Close connection
         client.close();
      }catch(IOException e) {
         e.printStackTrace();
      }
   }
}

我得到的消息：

错误：（28,44）java：unreported exception java.lang.ClassNotFoundException;必须被抓住或宣布被抛出

Answer 1

我知道发生了什么，但是为了参考，你可以把你的PlayerBoard课程？

参考我的想法：见 here 。

这是确保您能够正确读取对象的一般解决方案。如果服务器和客户端在不同的项目中，那么有两种方法可以获得正确的结果：

您必须拥有两个相同的PlayerBoard类（具有相同的包名称）。
PlayerBoard位于您提供给服务器和客户端项目的共享jar中。

对于您的演示（更有可能），如果您在同一个项目中同时拥有服务器和客户端，那么您无需担心上述注意事项。

剩下的就是：PlayerBoard必须实现Serializable。如果您有两个PlayerBoard类，则两者都必须以相同的方式实现Serializable。

我在ObjectInputStream上调用readObject（）时ClassNotFoundException

1 个答案: