Question

我有一个用PHP PDO（5.6）编写的方法应该返回最后插入的id。问题是插入已完成，但它返回0“string”。

stackoverflow中有很多帖子都有同样的问题，但我找不到适合我的解决方案。

我错过了什么？

以下是代码：

public static function set_values(array $arrSql = NULL) {

        try {            

            $fields="";
            $bindParamStr = "";
            $values = "";
            foreach ($arrSql as $tableName => $arrSetValues) {
                $table=$tableName;                                      //Inside 1 table
                foreach ($arrSetValues as $fieldName => $arrParam) {
                    $fields .= $fieldName.",";                          //Inside 1 field
                    $values .= "?,";
                    $bindParamStr[]=$arrParam;                   
                }
            }
            self::$sql= "INSERT INTO $tableName (".rtrim($fields,",").") VALUES (".rtrim($values,",").")";
            $stmt = self::$conn->prepare(self::$sql);
            $i=1;
            foreach ($bindParamStr as $bindPar) {
               if(count($bindPar)==1){
                   $stmt->bindValue($i,$bindPar[0]);
               } 
               else{
                   $stmt->bindValue($i,$bindPar[0],$bindPar[1]);
               }  
               $i++;
            }  


            self::$conn->beginTransaction();

            if($stmt->execute()){
                self::$conn->commit(); 
                $id= self::$conn->lastInsertId(); 
                return $id;
            }
            else{
                return FALSE;
            }

        } 
        catch (PDOException $e) {

            self::$arrCatchConnResult = self::saveLogMsg(["exceptionObjc"=>$e,"sql"=>self::$sql]);

            $msg = self::$arrCatchConnResult["displayMsgHTML"];

            self::$conn = null;

            if (self::$die) {

                die($msg);
            }
        }
    }

Answer 1

在提交交易之前获取插入ID：

$id = self::$conn->lastInsertId(); 
self::$conn->commit();

http://www.php.net/manual/en/pdo.lastinsertid.php#85129

PDO lastinsertId在事务中返回0，php - 5.6

1 个答案: