伙计们,我对javascript中的websockets有这个疑问,我想要将ip连接到服务器并且我没有想法这样做,我只想要ip' s ,我只想要那些现在连接的那些。
这是我的服务器:
var WebSocketServer = require('websocket').server;
var http = require('http');
var server = http.createServer(function(request, response) {
console.log((new Date()) + ' Received request for ' + request.url);
response.writeHead(404);
response.end();
});
server.listen(8080, function() {
console.log('Server is listening on port 8080');
});
wsServer = new WebSocketServer({
httpServer: server,
autoAcceptConnections: false
});
function originIsAllowed(origin) {
// put logic here to detect whether the specified origin is allowed.
return true;
}
wsServer.on('request', function(request) {
if (!originIsAllowed(request.origin)) {
// Make sure we only accept requests from an allowed origin
request.reject();
console.log((new Date()) + ' Connection from origin ' request.origin + ' rejected.');
return;
}
var connection = request.accept('echo-protocol', request.origin);
console.log((new Date()) + ' Connection accepted.');
connection.on('message', function(message) {
if (message.type === 'utf8') {
console.log('Received Message: ' + message.utf8Data);
var ipAddress = connection.remoteAddress;
console.log(ipAddress);
connection.sendUTF("pablo puta");
}
else if (message.type === 'binary') {
console.log('Received Binary Message of ' + message.binaryData.length + ' bytes');
connection.sendBytes(message.binaryData);
}
});
connection.on('close', function(reasonCode, description) {
console.log((new Date()) + ' Peer ' + connection.remoteAddress + ' disconnected.');
});
});
拜托,如果你能帮助我,我将非常感激。
答案 0 :(得分:3)
我相信你可以保留一个ips的对象:
var ips={};
connection.on('close', function(reasonCode, description) {
delete ips[connection.remoteAddress];
});
connection.on('open', function(reasonCode, description) {
ips[connection.remoteAddress]=true;
});
然后以某种方式回应:
Object.keys(ips);
给自己......
(我相信它必须是 this 而不是处理程序中的 connection ,但我不是专家......)