我希望回显两个与HTML页面相关的表的值。为此,我查询了表并在while循环中设置了一个while循环来回显输出。
每个数据库表都有一列unique_id,它是下一个表中的外键。使用用户的会话电子邮件查询第一个表以获取该unique_id。然后使用该值查询下一个表。
第一组数据echo很好,但下一个是空白的。
代码:
<!DOCTYPE HTML>
<html>
<head>
<title>Your Scorecards</title>
<link rel="icon" type="image/x-icon" href="../assets/favicon-32x32.png">
<link rel="stylesheet" href="stylesheet.css">
</head>
<body>
<?php include_once 'header.php'; ?>
<?php
$connect =mysqli_connect('localhost','root','','micaddy');
$id_query = mysqli_query($connect, "SELECT unique_id FROM users WHERE email = '{$_SESSION['login_user']}'");
$id_array = mysqli_fetch_assoc($id_query);
$uid = $id_array['unique_id'];
$result = mysqli_query($connect, "SELECT * FROM rounds WHERE user_id = '$uid'");
$rnd_id_query = mysqli_query($connect, "SELECT unique_id FROM rounds WHERE user_id = '$uid'");
$rnd_id_array = mysqli_fetch_assoc($rnd_id_query);
$round_id = $rnd_id_array['unique_id'];
$hole = mysqli_query($connect, "SELECT * FROM holes WHERE course_id = '$round_id'");
?>
<div class="container">
<div class="row">
<div class="col-lg-12">
<div class="panel panel-default">
<div class="panel-heading clearfix"><h3 class="panel-title"><strong>Your Rounds</strong></h3></div>
<?php while($row=mysqli_fetch_assoc($result)):?>
<div class="panel-body">
<div class="container-fluid">
<div class="row">
<div class="col-lg-5">
<div class="panel panel-default">
<div class="panel-heading"><h3 class="panel-title"><strong><?php echo $row['course_name'];?>   <?php echo $row['round_date']?> </strong></h3></div>
<div class="panel-body">
<table style="width:100%">
<tr>
<th>Hole Number</th>
 
<th>Yards</th>
 
<th>Par</th>
 
<th>Shots</th>
<?php while($hole_row=mysqli_fetch_assoc($hole)): ?>
<?php if($hole_row['course_id'] === $row['unique_id']){ ?>
<tr>
<td><?php echo $hole_row['hole_number']; ?></td>
<td><?php echo $hole_row['yards']; ?></td>
<td><?php echo $hole_row['par']; ?></td>
<td><?php echo $hole_row['shots']; ?></td>
</tr>
<?php } ?>
<?php endwhile; ?>
</tr>
</table>
</div>
</div>
</div>
</div>
</div>
</div>
<?php endwhile;?>
</div>
</div>
</div>
</div>
<?php include_once 'footer.php'; ?>
</body>
</html>
答案 0 :(得分:1)
您需要在外部循环中执行嵌套查询,因为您已经将java.lang.ClassCastException: maakesher.com.black.maakesher.psychoQuizzesActivity$1$1 cannot be cast to android.content.res.XmlBlock$Parser
更改为此:
$row = mysqli_fetch_assoc($rnd_id_query)