Question

我一直在寻找这个问题的答案，但我似乎无法在任何地方找到它。

我目前已经定义了装饰翻译服务的装饰器服务。但是，我只想在用户具有特定角色时修饰翻译服务。

services.yml

services:
    app.my_translator_decorator:
        class: MyBundle\MyTranslatorDecorator
        decorates: translator
        arguments: ['@app.my_translator_decorator.inner']
        public:    false

MyTranslatorDecorator.php

class MyTranslatorDecorator {

    /**
     * @var TranslatorInterface
     */
    private $translator;

    /**
     * @param TranslatorInterface $translator
     */
    public function __construct(TranslatorInterface $translator)
    {
        $this->translator = $translator;
    }

    // more code...

}

Answer 1

容器在运行时之前被“编译”。你不能根据上下文来装饰服务，它总会被装饰。

但是，在装饰器中，如果没有必要，可以添加一个guard子句来不执行自定义代码。

服务定义：

services:
    app.my_translator_decorator:
        class:     AppBundle\MyTranslatorDecorator
        decorates: translator
        arguments: ['@app.my_translator_decorator.inner', '@security.authorization_checker']
        public:    false

装饰：

<?php

namespace AppBundle;

use Symfony\Component\Security\Core\Authorization\AuthorizationCheckerInterface;
use Symfony\Component\Translation\TranslatorInterface;

class MyTranslatorDecorator implements TranslatorInterface
{
    private $translator;
    private $authorizationChecker;

    public function __construct(TranslatorInterface $translator, AuthorizationCheckerInterface $authorizationChecker)
    {
        $this->translator = $translator;
        $this->authorizationChecker = $authorizationChecker;
    }

    public function trans($id, array $parameters = [], $domain = null, $locale = null)
    {
        if (!$this->authorizationChecker->isGranted('ROLE_ADMIN')) {
            return $this->translator->trans($id, $parameters, $domain, $locale);
        }

        // return custom translation here
    }

    // implement other methods
}

Symfony：当用户拥有x角色时装饰服务

1 个答案: