Question

我是python的新手。我有下面的testfile。在testfile中重复相同的密钥。

下面是testfile输出：

Police Station1
kill: 10
dead: 20
Encounter: 5

Police Station2
kill: 15
dead: 20
Encounter: 6

Police Station3
kill: 20
dead: 15
Encounter: 10

如何使用python dict获取kill和dead details。我使用下面的代码。它只打印警察局3的详细信息，而不是第1和第2警察局。

以下是代码：

d = {}
with open('testfile.txt') as f:
    for line in f:
        if ":" not in line:
                continue
        key, value = line.strip().split(":", 1)
        d[key] = value

for k, v in d.iteritems():
    if k == 'dead':
        v = v.strip()
        print v
    if k == 'kill':
        v = v.strip()
        print v

我的输出低于输出：

15
20

我期待：

Police Station1
kill: 10
dead: 20

Police Station2
kill: 15
dead: 20

Police Station3
kill: 20
dead: 15

如何处理这种输出并获得上述输出。

注意：我不会坚持任何其他方法或解决方案，只要它能产生预期的预期效果

Answer 1

d = {}
holder = ""
with open('test.txt', 'r') as f:
    for line in f:
      line = line.strip()
      if line != "":
        if ":" not in line:
          d[line] = {}
          holder = line
        else:
          key, value = line.strip().split(":")
          d[holder][key] = value
        #here in the below line, you were overwriting the values each time
        #so only the values that were assigned last time will remain
        #In your case, {'kill': ' 20', 'Encounter': ' 10', 'dead': ' 15'}

        #d[key] = value

for k in d:
  print k
  for item in d[k]:
    if item != "Encounter":
      print item+" : "+d[k][item]

<强>输出：

警察局1

杀人：10

死了：20

警察局3

杀人：20

死了：15

警察局2

杀人：15

死了：20

Answer 2

你可以试试这个：

f = open('file.txt').read().splitlines()

f = [i.split() for i in f]
f = [i for i in f if len(i) > 0]


results = {''.join(f[i:i+4][0]):{f[i:i+4][b][0]:f[i:i+4][b][1] for b in range(1, 3)} for i in range(0, len(f), 4)}
print results

#gives you: {'PoliceStation1': {'dead:': '20', 'kill:': '10'}, 'PoliceStation2': {'dead:': '20', 'kill:': '15'}, 'PoliceStation3': {'dead:': '15', 'kill:': '20'}}

Answer 3

看起来你需要将容器嵌套一层。通过一些调整，再次使用您的代码：

dsub = d = {}
with open('testfile.txt') as f:
    for line in f:
        line = line.strip() # strip whitespace fore & aft
        if not line:  # ignore blank lines
            continue
        if ":" in line:
            key, value = line.split(":", 1)
            dsub[key] = value
        else:   # lines without colons are no long ignored: they're the outer-level keys
            dsub = d[line] = {} # create a new sub-dictionary 

for station, dsub in d.iteritems():
    print station, dsub['kill'], dsub['dead']

如果你想从字典中获取特定的条目，你不必遍历整个事情以期找到它 - 你可以直接查找它，如示例中所示上面dsub['dead']。

请注意，在字典迭代中，项目以任意顺序出现。如果这是一个问题，您可以使用sorted(d.iteritems())，也可以说from collections import OrderedDict并使用它而不是普通的dict。

用于多个重复键文件句柄的python dict

3 个答案: