Question

使用此代码从具有Basic身份验证的服务器获取JSON：

                    let config = URLSessionConfiguration.default
        let userPasswordData = "\(username!):\(password!)".data(using: .utf8)
        let base64EncodedCredential = userPasswordData!.base64EncodedString(options: Data.Base64EncodingOptions.init(rawValue: 0))
        let authString = "Basic \(base64EncodedCredential)"
        config.httpAdditionalHeaders = ["Authorization" : authString]
        let session = URLSession(configuration: config)

        let url = URL(string: "https://theforest.academy/api/v1/auth")
        let task = session.dataTask(with: url!) {
            (data, response, error) in
            if (response as? HTTPURLResponse) != nil {


                do {
                    if let data = data {
                       // let json1 = try JSONSerialization.jsonObject(with: data) as? [String: Any]
                        let json = try JSONSerialization.jsonObject(with: data, options: [], error: []) as? [String: Any]
                        if(json["valid"]) {
                            print(json["token"])
                        } else {
                            print("Invalid login")
                        }
                    }
                } catch {
                    print("Error deserializing JSON: \(error)")
                }

我收到以下错误

无法调用＆＃39; jsonObject＆＃39;使用类型＆＃39;的参数列表（带：数据，选项：[任意]，错误：[任何]）＆＃39;

Answer 1

查看documentation，您似乎只有两个选择：

jsonObject(with: Data, options: JSONSerialization.ReadingOptions = [])

和

jsonObject(with: InputStream, options: JSONSerialization.ReadingOptions = [])

我认为您正在寻找第一种方法。也许你会把它与

混淆

writeJSONObject(Any, to: OutputStream, options: JSONSerialization.WritingOptions = [], error: NSErrorPointer)

因此，简而言之，这种方法并不存在。这就是你收到错误的原因。

Answer 2

这是因为获取数据时我们没有处理错误。因此，我们需要安全地键入种姓数据，然后将其传递给JsonSerializer。这是代码。

    do {
        let data = try NSData.init(contentsOfFile: path) as Data
        let jsonArray = try JSONSerialization.jsonObject(with: data, options: .mutableContainers)
        print(jsonArray)
    } catch {
        print("Error getting data")
    }

无法调用＆＃39; jsonObject＆＃39;使用类型的参数列表

2 个答案: