Question

所以我有一个我已经解析过的Json文件，我想知道如何将Json文件中的信息传递给屏幕？继承人解析Json。

public String loadJSONFromAsset()
{
    String json = null;
    try
    {
        InputStream is = getAssets().open("JSON.json");

        int size = is.available();

        byte[] buffer = new byte[size];

        is.read(buffer);
        is.close();

        json = new String(buffer, "UTF-8");
    }
    catch(IOException ex)
    {
        ex.printStackTrace();
        return null;
    }
    return json;
}

JSON：

{"answers":[
{
"answer": "1"
},
{
"answer": "2"
},
{
"answer": "3"
},
{
"answer": "4"
},
{
"answer": "5"
}
]}

如何将“4”变为变量？我希望我的问题很清楚，如果没有，请评论。我想要做的只是输出其中一个数字。

Answer 1

使用此示例代码希望它能解决您的问题

 private void parseJson(String json) {
    try {
        JSONObject jsonObject = new JSONObject(json);
        JSONArray jsonArray = jsonObject.getJSONArray("answers");
        for (int i = 0; i < jsonArray.length(); i++){
            String answer = jsonArray.getJSONObject(i).getString("answer");
            Log.i(TAG,"answer: "+answer);
        }
    } catch (Exception e) {
        e.printStackTrace();
    }

}

Answer 2

解析JSON字符串。

JSONObject obj = new JSONObject(jsonString);
JSONArray answers = obj.getJSONArray("answers");
for (int i = 0; i < answers.length(); i++) {
    // this will loop though all answers
    JSONObject answerObj = answers.getJSONObject(i);
    String answer = answerObj.getString("answer");        
}

我建议搜索一些关于如何在java中解析JSON的例子，有很多例子和教程

Answer 3

你需要一个Java Json库。

    final JSONObject j = new JSONObject(parsed);

    JSONArray answers = j.getJSONArray("answers");

    System.out.println(answers.get(4));

Answer 4

You should used this sample code

 public String loadJSONFromAsset() {
    String json = null;
    try {
        InputStream is = getAssets().open("yourfilename.json");
        int size = is.available();
        byte[] buffer = new byte[size];
        is.read(buffer);
        is.close();
        json = new String(buffer, "UTF-8");
    } catch (IOException ex) {
        ex.printStackTrace();
        return null;
    }
    return json;
}

读取Json文件，这总是使用try和catch块

try {
        JSONObject obj = new JSONObject(loadJSONFromAsset());
        JSONArray m_jArry = obj.getJSONArray("answers");

        for (int i = 0; i < m_jArry.length(); i++) {

            JSONObject jo_inside = m_jArry.getJSONObject(i);
            String answer = jo_inside.getString("answer");

        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

输出解析的Json数据

4 个答案: