Question

player1_id | score1 | score2 | player2_id
-----------+--------+--------+-----------
         1 |      1 |      1 |          2
         3 |      1 |      1 |          1
        11 |      1 |      0 |         20
         5 |      1 |      1 |         55
       200 |      1 |      2 |         11
        17 |      1 |      1 |          7
        11 |      1 |      3 |          4
        11 |      1 |      1 |        100
        20 |      1 |      1 |          2
        20 |      2 |      1 |         33

玩家根据得分1和得分2获得“胜利”，“平局”或“失败”结果。我需要找到能够获得“胜利”，“平局”和“失败”结果的球员。在这种情况下，玩家11和20。

我被困在这里，任何帮助都非常感激。

Answer 1

如果我理解正确，你需要这个：

select p from (
    select player1_id as p, case when score1>score2 then 'W' when score1=score2 then 'D' when score1<score2 then 'L' end as res from your_table
    union all
    select player2_id as p, case when score1>score2 then 'L' when score1=score2 then 'D' when score1<score2 then 'W' end as res from your_table
) t
group by p
having count( distinct res ) = 3

Answer 2

您需要将所有玩家分成一列，以及您想要的分数或指标：

select p1
from ((select player1_id as p1, player2_id as p2, score1 as s1, score2 as s2
       from t
      ) union all
      (select player2_id as p1, player1_id as p2, score2 as s1, score1 as s2
       from t
      )
     ) t
group by p1
having sum( (s1 > s2)::int) > 0 and
       sum( (s1 = s2)::int) > 0 and
       sum( (s1 < s2)::int) > 0;

找到所有“赢”，“抽奖”和“失败”结果的玩家

2 个答案: