http://jsfiddle.net/gL1xynzr/3/适用于下拉菜单,是手机屏幕宽度的100%。
<div id="heroes-dropdown" class="ui dropdown">
<div class="text">Heroes</div>
<i class="dropdown icon"></i>
<div class="menu">
<a class="item"><i class="edit icon"></i> Edit Profile</a>
<a class="item"><i class="globe icon"></i> Choose Language</a>
<a class="item"><i class="settings icon"></i> Account Settings</a>
</div>
</div>
.menu
{
width:100vw;
max-width:440px;
}
但是,如果我在当前的左侧有其他下拉列表,则菜单不会从left=0px
开始,例如http://jsfiddle.net/no7ta6zc/3/
<div id="heroes-dropdown2" class="ui dropdown">
<div class="text">Heroes2</div>
<i class="dropdown icon"></i>
<div class="menu">
<a class="item"><i class="edit icon"></i> Edit Profile</a>
<a class="item"><i class="globe icon"></i> Choose Language</a>
<a class="item"><i class="settings icon"></i> Account Settings</a>
</div>
</div>
<div id="heroes-dropdown3" class="ui dropdown">
<div class="text">Heroes3</div>
<i class="dropdown icon"></i>
<div class="menu">
<a class="item"><i class="edit icon"></i> Edit Profile</a>
<a class="item"><i class="globe icon"></i> Choose Language</a>
<a class="item"><i class="settings icon"></i> Account Settings</a>
</div>
</div>
有谁知道如何让菜单的宽度填满整个屏幕的任何下拉菜单?
答案 0 :(得分:1)
您需要取消下拉列表div的相对位置,然后将所有下拉列表包装在另一个div中并制作该相对值。绝对定位的物品将根据它所在的第一个定位祖先进行定位:
include<stdio.h>
include<unistd.h>
void main(){
fork();
if fork();
if fork();
fork();
sleep(10);
}
&#13;
$('.ui.dropdown').dropdown();
&#13;
.menu {
Width: 100vw;
max-width: 440px;
}
.dropdown-wrapper {
/* make the wrapper relative */
position: relative;
}
.dropdown-wrapper .ui.dropdown {
/* cancel relative position if these divs */
position: static;
}
&#13;