我是c ++的新手,正在尝试开发合并排序代码。我用一个15号的样本数组测试了它,但代码提出的答案是不正确的。我无法弄清楚出了什么问题。这是我的代码:
#include <stdlib.h>
#include <stdio.h>
#include <iostream>
#include <string>
#include <fstream>
#include <vector>
#include <unistd.h>
#include <cstdlib>
using namespace std;
//two arrays, input
int initial[15] = {200,1,2,9,8,98,6,44,5,4,67,15,3,2,0};
//for output
int fin[15];
void sort(int* ini, int left, int right, int m);
//saperate the input in a recursion
void devide(int* ini, int left, int right){
int m;
if(left < right){
m = (left + right) / 2;
devide(ini, left, m);
devide(ini, m+1, right);
sort(ini, left, right, m);
}
}
//sorting
void sort(int* ini, int left, int right, int m){
//first half, start at the first element in the input array
int first_h = left;
//second half, start at the first element after the
// middle element in the input array
int second_h = m+1;
//index for output array
int out = left;
//comparing, if both half of array have element
while(first_h <= m && second_h <= right){
//put the smaller in the the output array
if(initial[first_h] < initial[second_h]){
fin[out] = initial[first_h];
first_h++;
}
else{
fin[out] = initial[second_h];
second_h++;
}
out++;
}
//if one of half of input is empty, put the rest element into the
// output array
while(first_h <= m){
fin[out] = initial[first_h];
out++;
first_h++;
}
while(second_h <= right){
fin[out] = initial[second_h];
out++;
second_h++;
}
}
int main(){
devide(initial, 0, 14);
for(int i =0; i<15; i++){
cout<<fin[i];
cout<<",";
}
return 0;
}
initiate []的输出,即fin []是:
5,4,67,15,3,2,0,200,1,2,9,8,98,6,44,
答案 0 :(得分:0)
所以你没有考虑到的一个小错误是,你正在传递指针数组ini但是在方法内仍然使用方法初始,还有一件事是,你应该接受一个临时数组将排序的值分配给你的ini数组。
所以你的代码看起来应该是这样的
void sort(int* ini, int left, int right, int m){
int first_h = left;
int second_h = m+1;
int out = left;
while(first_h <= m && second_h <= right){
if(ini[first_h] < ini[second_h]){
fin[out] = ini[first_h];
first_h++;
}
else{
fin[out] = ini[second_h];
second_h++;
}
out++;
}
while(first_h <= m){
fin[out] = ini[first_h];
out++;
first_h++;
}
while(second_h <= right){
fin[out] = ini[second_h];
out++;
second_h++;
}
for(int i=left; i<out; i++)
{
ini[i] = fin[i];
}
}
希望这有助于更好地理解算法!