Question

我正在为小型游戏创建一个回合制战斗系统，我收到了错误

TypeError：类型＆＃39;类型＆＃39;的对象没有len（）

在该行：

AImove = random.choice(AImove)

作为参考，AImove变量的设置如下：

AImove = [1,2]

我尝试将AImove = int和AImove = str添加到代码中，但我收到的错误与之前相同或"TypeError: object of type 'int' has no len()"

使用AImove的功能如下所示，我们将不胜感激。

def combat(health, turn, loop, gold, AImove):

    enemy_health = (random.choice(random_enemy_Health))
    enemy_attack = (random.choice(random_enemy_Attack))
    print("\nYou are fighting a" ,random.choice(enemies), "with an attack amount of" ,enemy_attack, "and a health amount of" ,enemy_health,".")
    while health > 0 and enemy_health > 0:
        if turn == 1:
            while loop == False:
                print("\nDo you want to attack or flee? Type '1' to attack and '2' to flee.")
                response=input()
                if response == "1":
                        enemy_health = enemy_health - attack
                        print("You attacked!")
                        loop = True                       
                elif response == "2":
                    hub_travel()
                    print ("You fled the battle, come back once you are stronger!")
                    loop = True
                else:
                    print ("Invalid number, try again")
                    continue
            turn = 2                                                    

        if turn == 2:
                AImove = random.choice(AImove)
                if AImove == 1:
                    print ("Enemy attacked!")
                    health = health - enemy_attack
                if AImove == 2:
                    print("Enemy missed!")
                turn = 1                                                    
                continue

Answer 1

您立即将AImove替换为random.choice的结果，之后是1或2，并在下一次迭代中尝试{{1} }（或random.choice(1)）解释了您所看到的例外情况。

您可以在那里使用另一个变量名称：

TypeError：类型＆＃39;类型＆＃39;的对象没有len（）

1 个答案: