我试图创建一个疯狂的libs游戏,用户可以在其中输入5个变量(名词,形容词,动词,副词,第二名词),然后在我的子类中用于不同的" libs&# 34 ;.问题是,当我输入我的参数时,它将它们打印为null。我确定有一种简单的方法可以为不同的toStrings使用相同的输入,但我不熟悉继承,并且不确定它的部分是如何工作的。
(我查看了其他toString null问题,但是没有一个对我的情况很有用,或者他们的构造者有问题。我相当确定我的没有错。)< / p>
这是我的Phrase超类:
public class Phrase
{
private String noun;
private String adjective;
private String verb;
private String adverb;
private String noun2;
public Phrase (String n, String a, String v, String ad, String n2)
{
n=noun;
a=adjective;
v=verb;
ad=adverb;
n2=noun2;
}
public String getNoun()
{return noun;}
public String getAdj ()
{return adjective;}
public String getVerb ()
{return verb;}
public String getAdverb ()
{return adverb;}
public String get2Noun ()
{return noun2;}
//i'll need the get methods in the libs classes and the set methods in the
while loop, if user wants to change parameters
public void setNoun (String Newnoun)
{noun=Newnoun;}
public void setAdj (String newAdj)
{adjective=newAdj;}
public void setVerb (String newVrb)
{verb=newVrb;}
public void setAdverb (String newAdv)
{adverb=newAdv;}
public void set2Noun (String newNoun2)
{noun2=newNoun2;}
}
这是我的子类:
public class Obama extends Phrase
{
public Obama(String noun, String adjective, String verb, String adverb,
String noun2)
{super (noun, adjective, verb, adverb, noun2);}
public String getNoun()
{return super.getNoun();}
public String getAdj ()
{return super.getAdj();}
public String getVerb ()
{return super.getVerb();}
public String getAdverb ()
{return super.getAdverb();}
public String get2Noun (String n)
{return super.get2Noun();}
public String toString()
{
return ("there is a " + super.getAdj() + " " + super.getNoun() +" on the
floor! It is " + super.getVerb() +"ing " + super.getAdverb() +". Next to it
is a " + super.get2Noun());
}
}
这是我的司机:
public class Madlibsdriver
{
static Scanner scan= new Scanner (System.in);
public static void main(String[] args)
{
System.out.print ("Welcome to Mad libs!");
System.out.println();
System.out.println("-------------------------------------------- ");
System.out.println("Enter a noun:");
String ip1= scan.nextLine();
System.out.println("Enter an adjective:");
String ip2= scan.nextLine();
System.out.println ("Enter a verb:");
String ip3= scan.nextLine();
System.out.println ("Enter an adverb (ex: angrily) :");
String ip4= scan.nextLine();
System.out.println ("Enter another noun:");
String ip5= scan.nextLine();
Phrase obama= new Obama(ip1, ip2, ip3, ip4, ip5);
System.out.println();
System.out.print (obama.toString());
}
}
答案 0 :(得分:2)
您已在构造函数中交换参数,您可以设置传入的值(而不是使用它们来设置本地字段)。使用anchor apple
关键字来捕获此类错误,例如
this