Question

大家好，并提前谢谢你，首先对不起，如果我的代码很混乱，我还在学习^^。我正在尝试制作具有不同属性的产品以及3个不同的图像（制作产品图库）和特征图像，我成功创建了属性和特征图像。问题是我无法存储的图库3图像（在DB或图像文件夹中都没有）我有两个表（product和productgallery），它们之间的关系是hasMany（我正在使用Laravel 5.4）

这是我在运行代码后得到的错误

x as &A

（对不起我的英语，肯定会让我更难理解我的问题）

ProductController

SQLSTATE[HY000]: General error: 1364 Field 'product_id' doesn't have a default value (SQL: insert into `product_galleries` (`updated_at`, `created_at`) values (2017-05-13 20:58:20, 2017-05-13 20:58:20))

上传请求（FormRequest）

 public function store(UploadRequest $request)
    {
        $product = new Product();
        $product->product_name = $request->product_name;
        $product->product_description = $request->product_description;
        if($request->hasFile('product_preview')) {
          $file = Input::file('product_preview');
          $filename = time(). '-' .$file->getClientOriginalName();
          $product->product_preview = $filename;
          $file->move(public_path().'/images/product-feature', $filename);
        }
        $product->category_id = $request->category_id;
        $product->color_id = $request->color_id;
        $product->size_id = $request->size_id;
        $product->material_id = $request->material_id;
        // $product->fantasia_id = $request->fantasia_id;
        $productgallery = new ProductGallery();
        if($request->hasFile('fileToUpload[]')) {
          $files = Input::file('fileToUpload[]');
          foreach ($request->$files as $photo) {
            $filename = time(). '-' .$photo->getClientOriginalName();
            $productgallery->product_images = $filename;
            $photo->move(public_path().'/images/product-gallery', $filename);
            $productgallery->product_id = 1;
          }
        }
        $product->save();
        $productgallery->save();
        return $this->create()->with('success', 'Uploaded Successfully');
    }

表格的视图

<?php

namespace App\Http\Requests;

use Illuminate\Foundation\Http\FormRequest;

class UploadRequest extends FormRequest
{
    public function authorize()
    {
        return true;
    }

    public function rules()
    {
        $rules = [
          'product_name'  => 'required|max:120',
          'category_id'   => 'required|integer',
          'product_preview' => 'required|image|mimes:jpeg,png,jpg,gif,svg',
        ];
        $fileToUpload = count($this->input('fileToUpload'));
        foreach(range(0, $fileToUpload) as $index) {
            $rules['fileToUpload.' . $index] = 'image|mimes:jpeg,bmp,png|max:2000';
        }
        return $rules;
    }
}

谢谢

Answer 1

我认为这就是你想要的。

这将为Product中传递的每张图片创建一个新的ProductGallery并创建新的$request->file('fileToUpload[]')：

$product = new Product();
$product->product_name = $request->product_name;
$product->product_description = $request->product_description;
if($request->hasFile('product_preview')) {
  $file = Input::file('product_preview');
  $filename = time(). '-' .$file->getClientOriginalName();
  $product->product_preview = $filename;
  $file->move(public_path().'/images/product-feature', $filename);
}
$product->category_id = $request->category_id;
$product->color_id = $request->color_id;
$product->size_id = $request->size_id;
$product->material_id = $request->material_id;
// $product->fantasia_id = $request->fantasia_id;


// First save the product (so that you have it's ID)
$product->save();
// Then create galleries
if($request->hasFile('fileToUpload[]')) {
  $files = Input::file('fileToUpload[]');
  foreach ($files as $photo) {
    $productgallery = new ProductGallery();
    $filename = time(). '-' .$photo->getClientOriginalName();
    $productgallery->product_images = $filename;
    $photo->move(public_path().'/images/product-gallery', $filename);
    $productgallery->product_id = $product->id; // Save it to the newly created product
    $productgallery->save();
  }
}
return $this->create()->with('success', 'Uploaded Successfully');

Answer 2

您需要查看Laravel关系API文档。这是一个链接，可以阅读更多相关信息Laravel 5.4 Eloquent Relationships

快速提示修复

您应该在数据库/迁移文件中添加外键
对于迁移，您只需添加

即可

$table->foreign('product_id')->references('id')->on('products');

并将此方法添加到产品模型

public function productgallery(){
 return $this->hasMany(Productgallery::class);
}

这是 Productgallery 模型

public function product(){
 return $this->belongsTo(Product::class);
}

注意：您仍然需要填写请求中的product_id字段

套餐解决方案

我建议您使用第三方软件包，因为它使用起来更少，更干净，更坚固。您可以查看spatie's medialibrary for Laravel

Laravel 5.4多次上传和插入数据

2 个答案: