我有一个方法可以计算模型中许多浮点属性的统计数据(主要是总和)。
模特
class GroupPlayer < ActiveRecord::Base
belongs_to :group
has_many :scored_rounds
has_many :rounds, dependent: :destroy
end
class Round < ActiveRecord::Base
belongs_to :group_player
end
class ScoredRound < Round
# STI
end
提供从其他方法调用的最多4个浮点属性的统计信息的方法,具体取决于我是否获得一个玩家或一组玩家的统计数据。 ScoredRound上的初始过滤器传递给方法(sr)
def method_stats(method,sr,grp)
rounds = sr.where.not(method => nil)
number_rounds = rounds.count
won = rounds.sum(method).round(2)
if method == :quality
dues = grp.options[:dues] * number_rounds
else
dues = grp.options["#{method.to_s}_dues"] * number_rounds
end
balance = (won - dues).round(2)
perc = dues > 0 ? (won / dues).round(3) : 0.0
[self.full_name,number_rounds,won,dues,balance,perc]
end
我在ScoredRounds中总结的4个属性中的3个可能没有设置(nil)如果玩家没有赢得该游戏,那么轮次被过滤。
一切正常,直到我决定增加使用轮数的限制。例如,如果我只希望传递给method_stats
的查询中最后25轮的状态,请致电:
def money_stats(grp,method,limit=100)
sr = self.scored_rounds.where.not(method => nil).order(:date).reverse_order.limit(limit)
method_stats(method,sr,grp)
end
同样,我刚刚在查询中添加了limit和order子句。所有记录都很好。
如果我在控制台中模拟程序而没有使用上述方法(或使用它们!)我会得到一个错误的总和
gp = GroupPlayer.find(123)
GroupPlayer Load (2.1ms) SELECT "group_players".* FROM "group_players" WHERE "group_players"."id" = $1 LIMIT $2 [["id", 123], ["LIMIT", 1]]
=> valid group player
sr = gp.scored_rounds.where.not(:quality => nil)
ScoredRound Load (1.7ms) SELECT "rounds".* FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> #<ActiveRecord::AssociationRelation [#<ScoredRound id: 5706, player_id: 123, group_player_id: 123, event_id: 12, type: "ScoredRound", date: "2016-11-04", team: 3, tee: "White", quota: 32, front: 15, back: 15, total: 30, created_at: "2016-11-04 14:18:27", updated_at: "2016-11-04 19:12:47", quality: 0.0, skins: nil, par3: nil, other: nil>,...]
sr.count
(1.5ms) SELECT COUNT(*) FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 44
sr.sum(:quality)
(1.0ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 354.166666666667
# Now if I add the order and limit clause
sr = gp.scored_rounds.where.not(:quality => nil).order(:date).reverse_order.limit(25)
ScoredRound Load (1.6ms) SELECT "rounds".* FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) ORDER BY "rounds"."date" DESC LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> => #<ActiveRecord::AssociationRelation [...]
sr.count
(1.1ms) SELECT COUNT(count_column) FROM (SELECT 1 AS count_column FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2) subquery_for_count [["group_player_id", 123], ["LIMIT", 25]]
=> 25
sr.sum(:quality)
(1.8ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> 354.166666666667
### This is the error, it return the sum off all records,
# not the limited???? if I use pluck and sum
sr.pluck(:quality)
=> [10.0, 11.3333333333333, 10.0, 34.0, 0.0, 7.33333333333333, 0.0, 0.0, 31.5, 0.0, 21.3333333333333, 0.0, 19.0, 0.0, 0.0, 7.5, 0.0, 20.0, 10.0, 28.0, 8.0, 9.5, 0.0, 3.0, 24.0]
sr.pluck(:quality).sum
=> 254.49999999999994
不知道我是否在AREL中发现了一个错误,或者我做错了什么。我用Round而不是STI ScoredRound尝试了相同的结果。
有什么想法吗?
答案 0 :(得分:1)
如果您注意到,SUM
的{{1}}结果与LIMIT
一样,都是相同的:
sr = gp.scored_rounds.where.not(:quality => nil)
sr.sum(:quality)
(1.0ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) [["group_player_id", 123]]
=> 354.166666666667
sr = gp.scored_rounds.where.not(:quality => nil).order(:date).reverse_order.limit(25)
sr.sum(:quality)
(1.8ms) SELECT SUM("rounds"."quality") FROM "rounds" WHERE "rounds"."type" IN ('ScoredRound') AND "rounds"."group_player_id" = $1 AND ("rounds"."quality" IS NOT NULL) LIMIT $2 [["group_player_id", 123], ["LIMIT", 25]]
=> 354.166666666667
因为LIMIT
会影响查询返回的行数而SUM
只返回一行,所以该函数适用于所有44条记录,而不是{ {1}}。这不是LIMIT
发生的事情,它只适用于查询返回的25条记录。
不知道我是否在AREL中发现了错误或我做错了什么
可悲的是,99.9%的时间不是错误,而是我们的错:(
答案 1 :(得分:0)
# File activerecord/lib/active_record/relation/calculations.rb, line 75
def sum(column_name = nil)
return super() if block_given?
calculate(:sum, column_name)
end
如果您致电sr.sum(:quality)
,则将质量汇总为列名,并计算给定列的值总和。